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3 years ago

Can someone help me please

Mathematics

1 answer:

riadik2000 [5.3K]3 years ago

6 0

Answer:

50 People

Step-by-step explanation:

The answer must be 50 people because if you add up all the data it shows

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How and what you spend your money on affects the tax deductions and credits that you’re eligible for. Visit the IRS website to s

bazaltina [42]

The tax credits and tax deductions currently offered include child tax credit, dependent care tax credit, etc.

It should be noted that a tax simply means rte compulsory levy that is paid by individuals and businesses to the government.

In this case, some of the tax credits and tax deductions currently offered include child tax credit, dependent care tax credit, etc.

If I can propose a tax credit or a deduction for an expense that isn’t currently on the list, it'll be a tax credit for aged people. This is important to help in relieving them of the burden of tax.

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8 0

1 year ago

Jessie installed 12 more axles than the number of engine blocks her friend Gus installed yesterday. Write an equation for g, the

jeka94

Answer:

g = j - 12

Step-by-step explanation:

Let's say Jessie installed j axles. Convert words to math:

- "12 more" = + 12

- "the number of engine blocks her friend Gus installed yesterday" = g

Put it together: g + 12. This is equal to j: j = g + 12. Solve for g:

j = g + 12

g = j - 12

8 0

2 years ago

Read 2 more answers

11 15/26 + [-17 5/13] =

aleksley [76]

11 15/26 + [-17 5/13] =

$11 \frac{15}{26} = \frac{301}{26}$

$-17 \frac{5}{13} = -\frac{226}{13}$

$\frac{301}{26} - \frac{226}{13}$

To subtract two fractions the denominators should be same

Least common denominator = 26

We multiply second fraction by 2

$\frac{301}{26} - \frac{452}{26}$

$\frac{301-452}{26}$

$\frac{-151}{26}$

8 0

3 years ago

A researcher drilled a hole in a die and filled it with a lead weight, then proceeded to roll it 209 times. The observed freque

ddd [48]

Answer:

Step-by-step explanation:

Given that the observed frequencies for the outcomes as follows:

To check this we can use chi square goodness of fit test.

$H_0: equally likely\\H_a: not equally likely$

(Two tailed test at 5% significance level)

Assuming equally likely expected observations are found out and then chi square is calculated as (0-E)^2/E

Df = 6-1 =5

Outcome Frequency Expected frequency (Obs-exp)^2/Exp

1 36 34.83333333 0.03907496

2 30 34.83333333 0.670653907

3 41 34.83333333 1.091706539

4 40 34.83333333 0.766347687

5 23 34.83333333 4.019936204

6 39 34.83333333 0.498405104

209 209 7.086124402

p value =0.214

Since p >alpha, we accept null hypothesis

It appears that the loaded die does not behave differently than a fair die at 5% level of significance

5 0

3 years ago

Seven subtracted from the product of 5 and a number is at least 24

Dovator [93]

Answer:

5a-7=24

5a=24+7

a=31/5

Step-by-step explanation:

8 0

2 years ago

Can someone help me please​

Can someone help me please