Let’s first see the probability of landing an even number. We have 6 sides, and 3 are labeled with an even number. So our chances of rolling a number cube are 3/6 (or 1/2 when simplified).
Next, the probability of rolling a number less then five is 4/6 (or 2/3 simplified), since we have 4 sides labeled with a number less than 5.
To compute two or more probabilities, we multiply them. In this case, the fractions already share the same denominator, 6 (because it’s a cube with 6 sides). So we get:
3/6 * 4/6
We then square 6, which is 36, and multiply 3 by 4, which is 12. This gives us 12/36, which is 1/3 in simplified form.
So there’s out answer: 1/3.
Answer:
26 - R = C
3 cars
Step-by-step explanation:
26-R = C
26-23 = 3
Answer:
Exact Form:
31/24
Decimal Form:
1.291¯6
Mixed Number Form:
1 7/24
Step-by-step explanation:
Well you subtract d from both sides with would make 2D-4=-8. Then you subtract four to both sides which is -12. Then you divide -12 by 2D which is 6. D=-6
Answer:
Step-by-step explanation:
<u>Equation Solving</u>
We are given the equation:
![\displaystyle x=\sqrt[3]{\frac{3y+16}{2y+9}}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20x%3D%5Csqrt%5B3%5D%7B%5Cfrac%7B3y%2B16%7D%7B2y%2B9%7D%7D)
i)
To make y as a subject, we need to isolate y, that is, leaving it alone in the left side of the equation, and an expression with no y's to the right side.
We have to make it in steps like follows.
Cube both sides:
![\displaystyle x^3=\left(\sqrt[3]{\frac{3y+16}{2y+9}}\right)^3](https://tex.z-dn.net/?f=%5Cdisplaystyle%20x%5E3%3D%5Cleft%28%5Csqrt%5B3%5D%7B%5Cfrac%7B3y%2B16%7D%7B2y%2B9%7D%7D%5Cright%29%5E3)
Simplify the radical with the cube:
Multiply by 2y+9
Simplify:
Operate the parentheses:
Subtract 3y and 
:
Factor y out of the left side:
Divide by 
:
ii) To find y when x=2, substitute:
