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sesenic [268]
3 years ago
6

Given that f(x) = x2 − 3x + 3 and g(x) = the quantity of x minus one, over four , solve for f(g(x)) when x = 5

Mathematics
1 answer:
weqwewe [10]3 years ago
6 0

Answer:

1

Step-by-step explanation:

To evaluate f(g(x)) when x = 5, evaluate g(5) then substitute the value obtained into f(x)

g(5) = \frac{5-1}{4} = \frac{4}{4} = 1, then

f(1) = 1² - 3(1) + 3 = 1 - 3 + 3 = 1

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jasenka [17]
For the second work sheet:
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Sorry if its not enough explanation, hope it helps!
8 0
2 years ago
- (4x4- 2x' +7x²+2 x - 1)=(x+3)
Gnom [1K]

Answer:

No solution?

Step-by-step explanation:

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4 0
3 years ago
use the elimination method to solve the system of equations. choose the correct ordered pair x-y=2 2x+3y=14
son4ous [18]

Answer:

x = 4

y = 2

Step-by-step explanation:

x - y = 2

   x = 2 + y

2x + 3y = 14

  2(2 + y) + 3y = 14

  4 + 2y + 3y = 14

  4 + 5y = 14

  5y = 10

   y = 2

x - y = 2

  x - 2 = 2

  x = 4

4 0
3 years ago
The temperature was −10 °F and dropped by 16 °F. Which statement represents the resulting temperature in degrees Fahrenheit? A −
algol13
<span>A
−10 + 16 = 6
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5 0
3 years ago
Read 2 more answers
Given the sequence 1/2 ; 4 ; 1/4 ; 7 ; 1/8 ; 10;.. calculate the sum of 50 terms
miv72 [106K]

<u>Hint </u><u>:</u><u>-</u>

  • Break the given sequence into two parts .
  • Notice the terms at gap of one term beginning from the first term .They are like \dfrac{1}{2},\dfrac{1}{4},\dfrac{1}{8} . Next term is obtained by multiplying half to the previous term .
  • Notice the terms beginning from 2nd term , 4,7,10,13 . Next term is obtained by adding 3 to the previous term .

<u>Solution</u><u> </u><u>:</u><u>-</u><u> </u>

We need to find out the sum of 50 terms of the given sequence . After splitting the given sequence ,

\implies S_1 = \dfrac{1}{2},\dfrac{1}{4},\dfrac{1}{8} .

We can see that this is in <u>Geometric</u><u> </u><u>Progression </u> where 1/2 is the common ratio . Calculating the sum of 25 terms , we have ,

\implies S_1 = a\dfrac{1-r^n}{1-r} \\\\\implies S_1 = \dfrac{1}{2}\left[ \dfrac{1-\bigg(\dfrac{1}{2}\bigg)^{25}}{1-\dfrac{1}{2}}\right]

Notice the term \dfrac{1}{2^{25}} will be too small , so we can neglect it and take its approximation as 0 .

\implies S_1\approx \cancel{ \dfrac{1}{2} } \left[ \dfrac{1-0}{\cancel{\dfrac{1}{2} }}\right]

\\\implies \boxed{ S_1 \approx 1 }

\rule{200}2

Now the second sequence is in Arithmetic Progression , with common difference = 3 .

\implies S_2=\dfrac{n}{2}[2a + (n-1)d]

Substitute ,

\implies S_2=\dfrac{25}{2}[2(4) + (25-1)3] =\boxed{ 908}

Hence sum = 908 + 1 = 909

7 0
2 years ago
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