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borishaifa [10]

2 years ago

6

Find the LCM of 14 and 18 using prime factorizations.

1 answer:

ElenaW [278]2 years ago

8 0

Answer:

126

Step-by-step explanation:

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Write an expression for the sequence of operations described below.

Akimi4 [234]

Triple t ⇒ 3t
add the result to u ⇒ 3t + u
multiply what you have by v ⇒ (3t + u)v

Since it is instructed not to simplify, we perform the distributive property of multiplication.

(3t + u)v = 3tv + uv

5 0

3 years ago

Alaine has 1 gallon of paint . She is going to pour it into a tray of paint that measures 10 inches wide ,12 inches long , and 5

r-ruslan [8.4K]

The tray measures 10 * 12 * 2 = 240 cubic inches
Since a gallon is 231 cubic inches, it will just fit into the tray.
The paint will be about a tenth of an inch from the top of the tray.

7 0

3 years ago

What does n= if<br> -6= n/-14 -5

zalisa [80]

Answer:

n=14

Step-by-step explanation:

-6=(n/-14)-5

-6+5 = n/-14

-1= n/-14

cross multiplication and striking of negative sign from both side.

n=14

4 0

3 years ago

Read 2 more answers

Using this equation for Wien’s Law (λ = 2898/T), the wavelength most emitted by the Sun (T = 6000K) is approximately: a. 48.3 µm

Paladinen [302]

<h2>Option C is the correct answer.</h2>

Step-by-step explanation:

By Wien’s Law we have

$\lambda =\frac{2898}{T}$

where λ is in μm and T is in K

Given that

T = 6000 K

Substituting

$\lambda =\frac{2898}{6000}=0.483\mu m$

Option C is the correct answer.

5 0

3 years ago

Suppose θ is an angle in the standard position whose terminal side is in Quadrant III and sec θ=61/60. Find the exact values of

Nataly_w [17]

Answer:

Part 1) $cos(\theta)=-\frac{60}{61}$

Part 2) $tan(\theta)=\frac{11}{60}$

Part 3) $cot(\theta)=\frac{60}{11}$

Part 4) $csc(\theta)=-\frac{61}{11}$

Part 5) $sin(\theta)=-\frac{11}{61}$

Step-by-step explanation:

we know that

If angle theta lie on Quadrant III

then

The function sine is negative

The function cosine is negative

The function tangent is positive

The function cotangent is positive

The function cosecant is negative

The function secant is negative

step 1

Find $cos(\theta)$

we know that

$cos(\theta)=\frac{1}{sec(\theta)}$

we have

$sec(\theta)=-\frac{61}{60}$ ----> the value must be negative

therefore

$cos(\theta)=-\frac{60}{61}$

step 2

Find $tan(\theta)$

we know that

$tan^{2} (\theta)+1=sec^{2} (\theta)$

we have

$sec(\theta)=-\frac{61}{60}$

substitute

$tan^{2} (\theta)+1=(-\frac{61}{60})^{2}$

$tan^{2} (\theta)+1=\frac{3,721}{3,600}$

$tan^{2} (\theta)=\frac{3,721}{3,600}-1$

$tan^{2} (\theta)=\frac{121}{3,600}$

$tan(\theta)=\frac{11}{60}$

step 3

Find $cot(\theta)$

we know that

$cot(\theta)=\frac{1}{tan(\theta)}$

we have

$tan(\theta)=\frac{11}{60}$

therefore

$cot(\theta)=\frac{60}{11}$

step 4

Find $csc(\theta)$

we know that

$cot^{2} (\theta)+1=csc^{2} (\theta)$

we have

$cot(\theta)=\frac{60}{11}$

substitute

$(\frac{60}{11})^{2}+1=csc^{2} (\theta)$

$\frac{3,600}{121}+1=csc^{2} (\theta)$

$\frac{3,721}{121}=csc^{2} (\theta)$

square root both sides

$csc(\theta)=-\frac{61}{11}$

step 5

Find $sin(\theta)$

we know that

$sin(\theta)=\frac{1}{csc(\theta)}$

we have

$csc(\theta)=-\frac{61}{11}$

therefore

$sin(\theta)=-\frac{11}{61}$

7 0

3 years ago

Read 2 more answers