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Anastaziya [24]

2 years ago

6

A projectile’s motion is modeled by the function given in the table, where x represents time in seconds and f(x) represents heig

ht above the ground. At what time is the projectile on the ground? – 80. 4 seconds 2 seconds 4. 6 seconds It will never hit the ground.

1 answer:

Pie2 years ago

4 0

Answer: 2 seconds

Step-by-step explanation:

got it right

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What is the greatest common factor (GCF) of the numerator and denominator in the rational expression below? 6x-18/x^2-5x+6

brilliants [131]

Numerator 6x - 18 = 6(x - 3)

Denominator x^2 - 5x + 6 = (x - 3)( x - 2)

8 0

3 years ago

Read 2 more answers

Find the value of x?

jekas [21]

Hello!
The left triangle have two same side length so the two bottom angles are the same which is (180-56)/2=62
See the left triangle bottom right angle and the right triangle bigger angle have the sum of 180 degree so the bigger angle=180-62=118
The right triangle also have two same sides so they also have same angle degree so x=(180-118)/2=31
Have a great day!

4 0

3 years ago

Stan's, marks, and wayne's ages are consecutive whole numbers. stan is the youngest, and wayne is the oldest. the sum of their a

White raven [17]

Stan's, Mark's and Wayne's ages are 35 , 36 and 37 years respectively.

<em><u>Explanation</u></em>

Stan's, Mark's and Wayne's ages are <u>consecutive whole numbers</u> and Stan is the youngest and Wayne is the oldest.

So, lets assume that Stan's, Mark's and Wayne's ages are $n, n+1$ and $n+2$

Given that, the sum of their ages is 108. So, the equation will be.....

$n+(n+1)+(n+2)=108\\ \\ 3n+3=108\\ \\ 3n=108-3=105\\ \\ n=\frac{105}{3}=35$

So, Stan's age is 35 years , Mark's age is (35+1)= 36 years and Wayne's age is (35+2)= 37 years.

4 0

4 years ago

Blossom typed 1/8 of her report on Monday. She typed 1/4 of the report of Tuesday. How much of the report does she need to type

DochEvi [55]

Answer:4

Step-by-step explanation:

4 0

3 years ago

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find the area of the trapezium whose parallel sides are 25 cm and 13 cm The Other sides of a Trapezium are 15 cm and 15 CM

Snezhnost [94]

$\huge\underline{\red{A}\blue{n}\pink{s}\purple{w}\orange{e}\green{r} -}$

Given - <u>A </u><u>trapezium</u><u> </u><u>ABCD </u><u>with </u><u>non </u><u>parallel </u><u>sides </u><u>of </u><u>measure </u><u>1</u><u>5</u><u> </u><u>cm </u><u>each </u><u>!</u><u> </u><u>along </u><u>,</u><u> </u><u>the </u><u>parallel </u><u>sides </u><u>are </u><u>of </u><u>measure </u><u>1</u><u>3</u><u> </u><u>cm </u><u>and </u><u>2</u><u>5</u><u> </u><u>cm</u>

To find - <u>Area </u><u>of </u><u>trapezium</u>

Refer the figure attached ~

In the given figure ,

AB = 25 cm

BC = AD = 15 cm

CD = 13 cm

<u>Construction</u><u> </u><u>-</u>

$draw \: CE \: \parallel \: AD \: \\ and \: CD \: \perp \: AE$

Now , we can clearly see that AECD is a parallelogram !

$\therefore$ AE = CD = 13 cm

Now ,

$AB = AE + BE \\\implies \: BE =AB - AE \\ \implies \: BE = 25 - 13 \\ \implies \: BE = 12 \: cm$

Now , In ∆ BCE ,

$semi \: perimeter \: (s) = \frac{15 + 15 + 12}{2} \\ \\ \implies \: s = \frac{42}{2} = 21 \: cm$

Now , by Heron's formula

$area \: of \: \triangle \: BCE = \sqrt{s(s - a)(s - b)(s - c)} \\ \implies \sqrt{21(21 - 15)(21 - 15)(21 - 12)} \\ \implies \: 21 \times 6 \times 6 \times 9 \\ \implies \: 12 \sqrt{21} \: cm {}^{2}$

Also ,

$area \: of \: \triangle \: = \frac{1}{2} \times base \times height \\ \\\implies 18 \sqrt{21} = \: \frac{1}{\cancel2} \times \cancel12 \times height \\ \\ \implies \: 18 \sqrt{21} = 6 \times height \\ \\ \implies \: height = \frac{\cancel{18} \sqrt{21} }{ \cancel 6} \\ \\ \implies \: height = 3 \sqrt{21} \: cm {}^{2}$

<u>Since </u><u>we've </u><u>obtained </u><u>the </u><u>height </u><u>now </u><u>,</u><u> </u><u>we </u><u>can </u><u>easily </u><u>find </u><u>out </u><u>the </u><u>area </u><u>of </u><u>trapezium </u><u>!</u>

$Area \: of \: trapezium = \frac{1}{2} \times(sum \: of \:parallel \: sides) \times height \\ \\ \implies \: \frac{1}{2} \times (25 + 13) \times 3 \sqrt{21} \\ \\ \implies \: \frac{1}{\cancel2} \times \cancel{38 }\times 3 \sqrt{21} \\ \\ \implies \: 19 \times 3 \sqrt{21} \: cm {}^{2} \\ \\ \implies \: 57 \sqrt{21} \: cm {}^{2}$

hope helpful :D

6 0

2 years ago