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vovikov84 [41]
3 years ago
14

(6.25•10^9)(9.8•10^16)

Mathematics
1 answer:
AVprozaik [17]3 years ago
7 0

Answer:

This is your answer.. you add exponents

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Can someone please help me on this one?
diamong [38]
Add the three angles and set them to 180
4x-13+15+x+18=180
5x+20=180
5x=160
x=32

Then plug in to get A and C
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Please help me and add steps so that I can understand
kap26 [50]

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Okay so what you are looking at is a triangle with a cross section. That is line segment PQ.You ae asked to find the length of PN. What you are given is the height(s) of NQ (5 units), QM (2 units) and PL (3 units). You can make an educated guess that line NP equals 4 units. Mainly because those two little arrows on lines LM and PQ (that means that the two lines are parallel). hope it helps...

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PLEASE HELP ME <br>...This is my homework and I don't understand how to do it.​
musickatia [10]

The probability that a point chosen at random lies in the shaded region is 0.28

<h3>Calculating the area of a shaded region and probability</h3>

From the question, we are to find the probability that a point chosen at random lies in the shaded region.

The shaded region is a triangle.

The probability that a point chosen at random lies in the shaded region = Area of the triangle / Area of the circle

First, we will calculate the unknown side of the triangle

Let the unknown side be x.

Then, from the <em>Pythagorean theorem</em>, we can write that

12² = 6² + x²

144 = 36 + x²

x² = 144 - 36

x² = 108

x = √108

x = 6√3

From formula,

Area of a triangle = 1/2 × base × height

Area of the triangle = 1/2 × 6 × 6√3

Area of the triangle = 18√3 square units

Now, we will determine the area of the circle

Area of a circle = πr²

Where r is the radius

From the given information,

Diameter of the circle = 12

But,

Radius = Diameter / 2

Therefore,

r = 12/2

r = 6

Thus,

Area of the circle = 3.14 × 6²

Area of the circle = 113.04 square units

Now,

The probability that a point chosen at random lies in the shaded region = 18√3 / 113.04

The probability that a point chosen at random lies in the shaded region = 0.2758

The probability that a point chosen at random lies in the shaded region ≈ 0.28

Hence, the probability is 0.28

Learn more on Calculating area of a shaded region here: brainly.com/question/23629261

#SPJ1

4 0
1 year ago
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