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Rudiy27
3 years ago
8

Why would a patient need to be in prone position?

Chemistry
1 answer:
dlinn [17]3 years ago
5 0
Reduced stroke volume and cardiac index results in a drop in blood pressure often seen when a patient is turned from supine to prone. Respiratory changes include a 30% to 35% decrease in respiratory compliance and increase in peak airway pressure. This in turn decreases venous return and cardiac output.
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Select all that apply. Any element can always be identified by its _____.
Gala2k [10]
The answer is c. number of protons and d. atomic number. The proton number can identify an element. And also the atomic number is equal to the number of protons.
4 0
3 years ago
Read 2 more answers
If the initial [NO2] is 0.260 M, it will take ________ s for the concentration to drop to 0.150 M. If the initial is 0.260 , it
Nitella [24]

The question is incomplete, here is the complete question:

At elevated temperature, nitrogen dioxide decomposes to nitrogen oxide and oxygen gas

NO_2\rightarrow NO+\frac{1}{2}O_2

The reaction is second order for NO_2 with a rate constant of 0.543M^{-1}s^{-1} at 300°C. If the initial [NO₂] is 0.260 M, it will take ________ s for the concentration to drop to 0.150 M

a) 1.01    b) 5.19     c) 0.299      d) 0.0880     e) 3.34

<u>Answer:</u> The time taken is 5.19 seconds

<u>Explanation:</u>

The integrated rate law equation for second order reaction follows:

k=\frac{1}{t}\left (\frac{1}{[A]}-\frac{1}{[A]_o}\right)

where,

k = rate constant = 0.543M^{-1}s^{-1}

t = time taken  = ?

[A] = concentration of substance after time 't' = 0.150 M

[A]_o = Initial concentration = 0.260 M

Putting values in above equation, we get:

0.543=\frac{1}{t}\left (\frac{1}{(0.150)}-\frac{1}{(0.260)}\right)\\\\t=5.19s

Hence, the time taken is 5.19 seconds

6 0
3 years ago
A chemist lectures about the following definition for acids and bases. The acid-base behavior is analyzed in terms of how electr
Y_Kistochka [10]

Answer:

the Lewis concept of acids and bases

Explanation:

8 0
3 years ago
Read 2 more answers
Sheena has a lump of sodium, a lump of potassium and a lump of lithium, but they’ve got mixed up and she doesn’t know which one
Arada [10]

Answer:

Explanation:

Just saw your request regarding answering this so here it is:

All of them belong of Group 1 in periodic table and thus are highly reactive! Pattern of reactivity for Group 1 (Alkali metals) increases as you move down the group as their radius keeps increasing and thus electrons can be easily lost. Thus, to ID the lumps, Sheena should look at their reactivity and she should get the following trend:

Most reactive: Potassium (K)

Intermediate: Sodium (Na)

Least reactive: Lithium (Li)

Hope it helps!

5 0
3 years ago
Hexane and octane are mixed to form a 45 mol% hexane solution at 25 deg C. The densities of hexane and octane are 0.655 g/cm3 an
avanturin [10]

Answer:

The required volume of hexane is 0.66245 Liters.

Explanation:

Volume of octane = v=1.0 L=1000 cm^3

Density of octane= d = 0.703 g/cm^3

Mass of octane ,m= d\times v=0.703 g/cm^3\times 1000 cm^3=703 g

Moles of octane =\frac{m}{114 g/mol}=\frac{703 g}{114 g/mol}=6.166 mol

Mole percentage of Hexane = 45%

Mole percentage of octane = 100% - 45% = 55%

55\%=\frac{6.166 mol}{\text{Total moles}}\times 100

Total moles = 11.212 mol

Moles of hexane :

45%=\frac{\text{moles of hexane }}{\text{Total moles}}\times 100

Moles of hexane = 5.0454 mol

Mass of 5.0454 moles of hexane,M = 5.0454 mol × 86 g/mol=433.9044 g

Density of the hexane,D = 0.655 g/cm^3

Volume of hexane = V

V=\frac{M}{D}=\frac{433.9044 g}{0.655 g/cm^3}=662.4494 cm^3\approx 0.66245 L

(1 cm^3= 0.001 L)

The required volume of hexane is 0.66245 Liters.

5 0
3 years ago
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