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adelina 88 [10]
4 years ago
14

Anions are those elements on the upper right side of the periodic table, excluding the Noble gases, that gain electrons when the

y ionize. T or F?
Chemistry
1 answer:
Gala2k [10]4 years ago
3 0

Answer:

True

Explanation:

The given statement is true. The elements on the upper right side of periodic table accept the electrons because of higher electronegativity values and form anions.

For example:

Consider the halogens. All halogens accept the one electron per atom to complete the octet and form anion. when they combine with metals metals loses their electrons to halogens atoms and form cations while halogens accept the electrons and form anion.

Consider the sodium chloride salt. The sodium metal loses its one valance electron which is accepted by chlorine.

Na⁺Cl⁻

Magnesium bromide:

To complete the octet bromine required one electron. By gaining the one electron it showed -1 oxidation state.

When bromine combine with magnesium both formed MgBr₂.

The one atom of Mg have +2 oxidation state while bromine have -1 that's why to make the overall compound neutral two bromine atoms combine with one atom of magnesium.

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How many total atoms are in 0.670 g of p2o5?
scoray [572]

The molecular formula for compound is  P_{2}O_{5} mass of compound is 0.670 g.

To calculate number of atoms first calculate number of moles in the compound as follows:

n=\frac{m}{M}

Molar mass of  P_{2}O_{5} is 283.886 g/mol, thus,

n=\frac{0.670 g}{283.886 g/mol}=0.00236 mol

Thus, number of mole of P_{2}O_{5} is 0.00236 mol.

From the molecular formula 1 mole of P_{2}O_{5} has 2 mol of P (phosphorus) and 5 mol of O (oxygen).

Thus, number of moles of P and O in 0.00236 mol of P_{2}O_{5} will be:

n_{P}=2\times 0.00236 mol=0.00472 mol

Similarly,

n_{O}=5\times 0.00236 mol=0.0118 mol

Now, in 1 mol of an element there are 6.023\times 10^{23} atoms.

Number of atoms of P will be:

N_{P}=0.00472\times 6.023\times 10^{23}=2.84\times 10^{21}atoms

Similarly, number of atoms of O will be:

N_{O}=0.0118\times 6.023\times 10^{23}=7.11\times 10^{21}atoms

Total number of atoms will be sum of number of atoms of P and O:

N_{Total}=N_{P}+N_{O}=2.84\times 10^{21}+7.11\times 10^{21}=9.95\times 10^{21} atoms

Therefore, total number of atoms in P_{2}O_{5} will be 9.95\times 10^{21} atoms.

8 0
3 years ago
A molecule has three bonded atoms around the central atom. The central atom does not have any lone pairs. What is the geometry o
adelina 88 [10]

Answer:

trigonal planar

Explanation:

Tri=three, three-dimensional arrangement of the atoms that constitute a molecule.

5 0
3 years ago
Choose the number of significant figures indicated. 0.06
jeka94
One-
The 6 is the only significant figure.
8 0
4 years ago
Read 2 more answers
How many grams of Na2So4 would be formed if 0.75 moles of NaOH reacted?
Nata [24]

Answer:

\boxed{\text{53 g }}

Explanation:

You don't give the reaction, but we can get by just by balancing atoms of Na.

We know we will need the partially balanced equation with masses, moles, and molar masses, so let’s gather all the information in one place.

M_r:                                 142.04  

             2NaOH + … ⟶ Na₂SO₄ + …  

n/mol:      0.75

1. Use the molar ratio of Na₂SO₄ to NaOH to calculate the moles of NaF.

Moles of Na₂SO₄ = 0.75 mol NaOH × (1 mol Na₂SO₄/2 mol NaOH

= 0.375 mol Na₂SO₄

2. Use the molar mass of Na₂SO₄ to calculate the mass of Na₂SO₄.

Mass of Na₂SO₄ = 0.375 mol Na₂SO₄ × (142.04 g Na₂SO₄/1 mol Na₂SO₄) = 53 g Na₂SO₄

The reaction produces \boxed{\text{53 g }} of Na₂SO₄.

4 0
3 years ago
**25 POINTS**. I doubt anyone will do this but it's worth a try to ask. To do this exercise, you will need fifteen containers, f
Travka [436]

Answer:

done not that hard

Explanation:

6 0
3 years ago
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