Hey there!:
moles of AgNO3 = 100 x 0.1 / 1000 = 0.01
moles of NaCl = 100 x 0.200 / 1000 = 0.02
volume of solution = 100 + 100 = 200 mL
mass of solution = 200 x 1 = 200 g
temperature rise = 25.30 - 24.60 = 0.70ºC
Therefore:
Q = m* Cp* ΔT + Cp* ΔT =
200* 4.184 * 0.70 + 15.5 * 0.70 =
Q = 596.61 J
Given the reaction:
Q = 596.61 J
NaCl(aq) + AgNO3(aq)--------> AgCl(s) + NaNO3(aq)
1 mole NaCl ------ 1 mole AgNO3 ------ 1 mole AgCl
0.02 moles NaCl ----- 0.01 moles AgNO3
So:
ΔH = - Q / T
ΔH = - 596.61 * 10⁻³ / 0.01
ΔH = - 59.66 kJ
Hope that helps!
Tetrahedral molecular geometry is the only one that can exist for sp3 hybridized center atoms.
<h3>Which chemical contains an sp3 hybridized central atom?</h3>
- An atom that is bound and a nonponding pair of electrons are the two different kinds of electron domains.All bonded atoms count as one electron domain on the center atom, regardless of whether they are connected by a single, double, or triple bond.
- There are five fundamental geometries for electron domains. The core oxygen atom in the water molecule has six valence electrons.The 6 valence electrons of oxygen are arranged in hybridized sp3 orbitals, resulting in 2 paired and 2 free electrons.
- One s orbital and three p orbitals combine to generate four sp3 orbitals, each of which has a 25% s character and a 75% p character. This process is known as sp3 hybridization.
- An example of CO2 can be used to illustrate how lone pairs of electrons make up an SP3 hybrid orbital.We are only able to count bond pairs or lone bonds.
To learn more about sp3 refer
brainly.com/question/28359475
#SPJ4
Answer:
Drip rate = 2 ml/h
Explanation:
Given:
Amount of insulin = 500 unit
Amount of saline = 250 ml
Required infusion rate = 4.0 units/h
Find:
Drip rate
Computation:
Concentration = Units of insulin / Volume of saline
= 500 / 250
Concentration = 2 units/ml
Drip rate = Infusion rate / concentration
Drip rate = 4 / 2
Drip rate = 2 ml/h
