How many grams of S are in 475 g of SO2?
1 answer:
There are 237. 5 g of Sulfur,S in 475 g of SO2?
<h3 /><h3>Calculation of grams of Sulfur</h3>From the question, we can say that
- The molar mass of sulfur = 32 g/mol
- The molar mass of oxygen = 16 g/mol
Therefore,
The molar mass for SO2 = 32 + (16 × 2) g/mol = 64 g/mol
Now,
If 1 mole of SO2 contains 1 mole of S
Then 64 g of SO2, will contain 32g of S;
Such that
475 g of SO2 will give { } = 237. 5 g of Sulfur.
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<h2>Answer:
</h2>
Explanation:
The chemical equation of the reaction that occurs when reacts with
is
→
moles of
requires
moles of
.
mole of
requires
moles of
.
Given that we have moles of
.
moles of
requires
moles of
.
But we have moles of
.
So, will be consumed first.
So, is the limiting reagent.
Answer:
Therefore, the rate of change in the amount of salt is
Explanation:
Given:
Initial volume of water lit
Flowing rate = 5
The rate of change in the amount of salt is given by,
( Rate of salt enters tank - rate of sat leaves tank )
Since tank is initially filled with water so we write that,
Let amount of salt in the solution is ,
Therefore, the rate of change in the amount of salt is