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2 years ago

PLEEASE HELP TIMED WILL GIVE BRAINLIEST TO CORRECT ANSWER NLY PLEASEEEE HELPPPP

Chemistry

2 answers:

Arturiano [62]2 years ago

8 0

Answer:

1) 1.15 mol

2) M=0.45

3) 22.5 mL

4) 6.25 mL

Explanation:

550 mL= 0.55 L

M= mol solute/ L solution

mol solute= M * L solution

mol solute= (2.1 M * 0.55 L ) M=1.15 mol solute

155 mL = 0.155 L

80 g -> 1 mol NH4NO3

5.61 g -> x

x= (5.61 g * 1 mol NH4NO3)/80 g x= 0.07 mol NH4NO3

M=(0.07 mol NH4NO3)/0.155 L M=0.45

3) M1V1=M2V2

V1= M2V2/M1

V1= (0.500 M * 0.225 L)/5.00 M V1=0.0225 L =22.5 mL

4) M1V1=M2V2

V1= M2V2/M1

V1= (0.25 M * 0.45 L)/ 18.0 M

V1=6.25 x 10^-3 L = 6.25 mL

Grace [21]2 years ago

6 0

Answer:

Explanation:

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The solubility KI is 50 g in 100 g of H2O at 20 °C. if 110 grams of ki are added to 200 grams of H2O ________

Salsk061 [2.6K]

The solubility KI is 50 g in 100 g of H₂O at 20 °C. if 110 grams of ki are added to 200 grams of H₂O the solution will be saturated.

<h3>What is solubility?</h3>

Solubility is a condition where the solute is fully dissolved in the solvent. When fully mixed with the solvent.

Given that 50 g of KI is added to 100 g of water at 20 °C it means 100 g of water can dissolve a maximum of 50 g of KCl.

1 g of water will dissolve an quantity of 0.5 g of KCl.

To assay for 200 g of water: 200 g of water can disintegrate a maximum of (0.5) x 200 g of KCl.

The maximum amount of KCl that will dissolve is 100 g

Actualised amount dissolved = 110 g

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110 g > 100 g

Thus, the solution is saturated.

To learn more about solubility, refer to the below link:

brainly.com/question/8591226

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1 year ago

a sealed container filled with argon gas at 35 c has a pressure of 832 torr. if the volume of the container is decreased by a fa

lesya692 [45]

Answer:

If the volume of the container is decreased by a factor of 2 the pressure is is increased by the same factor to 1664 torr.

Explanation:

Here we have Boyle's law which states that, at constant temperature, the volume of a given mass of gas is inversely proportional to its pressure

V ∝ 1/P or V₁·P₁ = V₂·P₂

Where:

V₁ = Initial volume

V₂ = Final volume = V₁/2

P₁ = Initial pressure = 832 torr

P₂ = Final pressure = Required

From V₁·P₁ = V₂·P₂ we have,

P₂ = V₁·P₁/V₂ = V₁·P₁/(V₁/2)

P₂ = 2·V₁·P₁/V₁ = 2·P₁ = 2× 832 torr = 1664 torr

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3 years ago

What is the empirical formula for C8H20F4

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The given formula of $C_{8} H_{2} O F_{4}$ can be written as $C_{4} H_{10}-C_{4} H_{10}-F_{4}$

Explanation:

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2 years ago