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Vadim26 [7]
3 years ago
7

PLEEASE HELP TIMED WILL GIVE BRAINLIEST TO CORRECT ANSWER NLY PLEASEEEE HELPPPP

Chemistry
2 answers:
Arturiano [62]3 years ago
8 0

Answer:

1) 1.15 mol

2) M=0.45

3) 22.5 mL

4) 6.25 mL

Explanation:

1)

550 mL= 0.55 L

M= mol solute/ L solution

mol solute= M * L solution

mol solute= (2.1 M * 0.55 L )        M=1.15 mol solute

2)

155 mL = 0.155 L

80 g  -> 1 mol NH4NO3

5.61 g -> x

x= (5.61 g * 1 mol NH4NO3)/80 g       x= 0.07 mol NH4NO3

M=(0.07 mol NH4NO3)/0.155 L         M=0.45

3) M1V1=M2V2

V1= M2V2/M1

V1= (0.500 M * 0.225 L)/5.00 M             V1=0.0225 L =22.5 mL

4) M1V1=M2V2

V1= M2V2/M1

V1= (0.25 M * 0.45 L)/ 18.0 M

V1=6.25 x 10^-3 L = 6.25 mL

Grace [21]3 years ago
6 0

Answer:

?

Explanation:

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Answer:

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Explanation:

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<em>Mass Cu:</em>

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0.099moles Cu * (6.022x10²³atoms / 1mol) =

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If 115grams of a substance reacts with 84grams of another substance, what will be the mass of the products after the reaction?
AysviL [449]
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What is the pH of a solution that is 0.40 M NaBrO and 0.50 M HBrO (hypobromous acid) (Ka for HBrO = 2.3 x 10^-9)
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Answer

pH=8.5414

Procedure

The Henderson–Hasselbalch equation relates the pH of a chemical solution of a weak acid to the numerical value of the acid dissociation constant, Kₐ. In this equation, [HA] and [A⁻] refer to the equilibrium concentrations of the conjugate acid-base pair used to create the buffer solution.

pH = pKa + log₁₀ ([A⁻] / [HA])

Where

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pKa = negative logarithm of Ka

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Answer: ?

Explanation:

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Answer:

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Explanation:

Given:

Total amount = ? or assume x

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