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xenn [34]
3 years ago
13

Micah was asked to add the following expressions: 3x2−x−9x2+3x+2+−2x2+2x+5x2+3x+2 First, he combined like terms in the numerator

and kept the common denominator. x2+x−4x2+3x+2 Next, he simplified the expression by canceling the like term, x2. His final, simplified answer was: x−43x+2 Did Micah add the expressions correctly? Explain your answer using complete sentences.
Mathematics
1 answer:
shtirl [24]3 years ago
5 0

Micah was asked to add the following expressions:

\frac{3x^2-x-9}{x^2+3x+2} + \frac{-2x^2+2x+5}{x^2+3x+2}

First, he combined like terms in the numerator and kept the common denominator

First step is correct. He added the like terms in the numerator, because the denominators are same.

3x^2 -x -9 -2x^2+2x+5becomes x^2 +x -4

So he got , \frac{x^2+x-4}{x^2+3x+2}

In the next step, he cannot cancel out x^2 from the top and bottom . Because x-4 and 3x+2  are added with x^2

If we have x^2 is multiplied with other terms at the top and bottom , then we can cancel out x^2.

So Micah added the expression incorrectly. Final answer is not correct.

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Please please please help and solve this with steps, much help needed thank you :) 20 points for this!
leonid [27]

Answer:

y=\sqrt{\frac{x^4-6x^2+12x+c_1}{2}},\:y=-\sqrt{\frac{x^4-6x^2+12x+c_1}{2}}

(Please vote me Brainliest if this helped!)

Step-by-step explanation:

\frac{dy}{dx}y=x^3+2x-5x+3

\mathrm{First\:order\:separable\:Ordinary\:Differential\:Equation}

  • \mathrm{A\:first\:order\:separable\:ODE\:has\:the\:form\:of}\:N\left(y\right)\cdot y'=M\left(x\right)

1. \mathrm{Substitute\quad }\frac{dy}{dx}\mathrm{\:with\:}y'\:

y'\:y=x^3+2x-5x+3

2. \mathrm{Rewrite\:in\:the\:form\:of\:a\:first\:order\:separable\:ODE}

yy'\:=x^3-3x+3

  • N\left(y\right)\cdot y'\:=M\left(x\right)
  • N\left(y\right)=y,\:\quad M\left(x\right)=x^3-3x+3

3. \mathrm{Solve\:}\:yy'\:=x^3-3x+3:\quad \frac{y^2}{2}=\frac{x^4}{4}-\frac{3x^2}{2}+3x+c_1

4. \mathrm{Isolate}\:y:\quad y=\sqrt{\frac{x^4-6x^2+12x+4c_1}{2}},\:y=-\sqrt{\frac{x^4-6x^2+12x+4c_1}{2}}

5. \mathrm{Simplify}

y=\sqrt{\frac{x^4-6x^2+12x+c_1}{2}},\:y=-\sqrt{\frac{x^4-6x^2+12x+c_1}{2}}

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