Answer:
water and air
Explanation:
The examples of medium from this problem is water and air.
A medium is an agency or a means of propagating energy, waves or even facilitating a chemical reaction.
Fluids are very good medium in chemistry for chemical reactions. The two most common media used are air and water.
In physics, a vacuum is an empty space that has been evacuated. It also serves as a medium to study some physical phenomenon.
<u>Answer:</u>
"Boyle's Law" is based on the graph that is shown below.
<u>Explanation:</u>
Boyle's law or Boyle – Mariotte law or Mariotte's law, is an experimental gas law that discusses how a gas's pressure tends to rise as the container volume start declining. This shows the relationship between pressure and volume for a fixed mass at a constant temperature, i.e., number of a gas molecules.This rule visualizes the actions of gas molecules in a confined space. This law can be understood from following equation:
p₁V₁ = p₂V₂
Above the product of the initial volume and pressure is equal to the product of the volume and pressure after a change.
Burning, cooking
Explanation:
Chemical changes that happens in school are:
Cooking of meals
Burning of wastes
Chemical reactions in laboratories
Rusting of iron used in construction
- A chemical change is a change that produces new kinds of substances.
- These changes are usually accompanied by energy and mass changes.
- Most of such changes are not reversible.
Chemical changes are driven by change in chemical properties of matter.
In a school, iron components might begin to rust. This is a chemical change.
learn more:
Chemical change brainly.com/question/9388643
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Answer:
m = 4450 g
Explanation:
Given data:
Amount of heat added = 4.45 Kcal ( 4.45 kcal ×1000 cal/ 1kcal = 4450 cal)
Initial temperature = 23.0°C
Final temperature = 57.8°C
Specific heat capacity of water = 1 cal/g.°C
Mass of water in gram = ?
Solution:
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
ΔT = 57.8°C - 23.0°C
ΔT = 34.8°C
4450 cal = m × 1 cal/g.°C × 34.8°C
m = 4450 cal / 1 cal/g
m = 4450 g
