List the elements Cs, Ca, Ne, Na, Ar in order of decreasing first ionization energy

1 answer:

3 0

The ionization energy increases from left to right and from bottom to top in the periodic table, like in diagonal

Ar,
Ne,
Cs,
Ca,
Na

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The following characteristics describe which type of mixture, homogeneous or heterogeneous? The substance is mixed uniformly thr

alexira [117]

The correct answer to this question is letter "A. homogeneous mixture." The following characteristics describe the type of mixture, which is a homogeneous mixture. The substance is mixed uniformly throughout and each part of <span>the substance contains the same ratio of materials with the same properties</span>

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3 years ago

Can someone help me with this molar mass problem?[It’s the last one]

quester [9]

Answer:

$54.18 \times 10^{23} \ moles$ in 3 mole of $Al_2(SO_4)_3$

Explanation:

It is clear that in the given $1\ mole$ of $Al_2(SO_4)_3$ have $3\ ions$ of $SO_4^2^-$

Therefore 3 moles of $Al_2(SO_4)_3$ will have $3\times3=9 \ ions$ of $SO_4^2^-$

Since 1 ion of anything is equivalent to $6.02\times10^{23} \ moles$

Therefore 3 moles of $Al_2(SO_4)_3$ will have $3\times3=9 \ ions$ of $SO_4^2^-$

Which is equivalent to $9 \times6.02\times10^{23}=54.18\times10^{23} \ moles$

Thus 3 moles of $Al_2(SO_4)_3$ gives $54.18\times10^{23} \ moles$ of $SO_4^2^-$ .

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3 years ago

What can be said about an endothermic reaction with a negative entropy change?

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The statement is false because endothermic reactions have a positive enthalpy change, because heat is being added to the system because it requires more energy to react

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"A neutron turns into a proton and an electron
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If a 0.4681 g Mg strip reacts with 0.650 M HCl in a 139.3 mL flask at 25oC, what is the minimum volume (mL) of HCl needed to com

Marizza181 [45]

The reaction between the magnesium, Mg, and the hydrochloric acid, HCl is given in the equation below,

Mg + 2HCl --> H2 + MgCl2

The number of moles of HCl that is needed for the reaction is calculated below.
n = (0.4681 g Mg)(1 mol Mg/24.305 g Mg)(2 mol HCl/1 mol Mg)
n = 0.0385 mols HCl

From the given concentration, we calculate for the required volume.
V = 0.0385 mols HCl/(0.650 mols/L)
V = 0.05926 L or 59.26 mL

<em>Answer: 59.26 mL of HCl</em>

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3 years ago