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VashaNatasha [74]
3 years ago
10

Johana works in the crime lab at the New York City Police Department. A woman’s shoe was found at a crime scene. Johana measures

it and then uses the following function equation to predict the estimated height of the suspect: y =1.19x+56 where x represents a woman’s shoe size and y represents the estimated likely height of the woman in inches. a. Using a calculator, determine an ordered pair that is a solution to this function. b. Interpret your solution in the context of this problem, using one or more complete sentences. Use the information given in the problem when describing the values of your input and output. 58
Mathematics
1 answer:
madam [21]3 years ago
7 0

Answer:

(7, 64.33)

Step-by-step explanation:

For a woman suspect whose shoe size was found at the crime scene, the equation which can be used to predict the estimated height is given as:

y=1.19x+56,$ where:\\x = woman's shoe size\\ y= the estimated likely height of the woman in inches.

(a)Let x=7

Then:  y =1.19(7)+56=64.33

An ordered pair that is a solution to the function is (7, 64.33)

(b) The estimated height of a woman who is of shoe size 7 is 64,33 inches.

Petra242002
2 years ago
Why did you put 7 for x
Petra242002
2 years ago
Why did you put 7 for x?
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OLga [1]

Answer:

73 dimes and 133 nickels

Step-by-step explanation:

$13.95 = 1395 cents

5n + 10d = 1395     (since each nickel is 5 cents and each dime is 10 cents)

5n = 1395 - 10d      (subtract 10d from both sides to solve for n)

n = 279 - 2d

n + d = 206

279 - 2d + d = 206   (substitute n with the previous expression)

279 - d = 206         (add variable d and -2d)

-d = -73        (solve for d and divide both sides by negative 1)

d = 73          

n + 73 = 206 (solve for n and subtract both sides by 73)  

n = 133

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3 years ago
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Answer:

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Step-by-step explanation:

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3 years ago
A student on a piano stool rotates freely with an angular speed of 2.85 rev/s . The student holds a 1.50 kg mass in each outstre
Vlad1618 [11]

Answer:r'=0.327 m

Step-by-step explanation:

Given

N=2.85 rev/s

angular velocity \omega =2\pi N=17.90 rad/s

mass of objects m=1.5 kg

distance of objects from stool r_1=0.789 m

Combined moment of inertia of stool and student =5.53 kg.m^2

Now student pull off his hands so as to increase its speed to 3.60 rev/s

\omega _2=2\pi N_2

\omega _2=2\pi 3.6=22.62 rad/s

Initial moment of inertia of two masses I_0=2mr_^2

I_0=2\times 1.5\times (0.789)^2=1.867

After Pulling off hands so that r' is the distance of masses from stool

I_0'=2\times 1.5\times (r')^2

Conserving angular momentum

I_1\omega =I_2\omega _2

(5.53+1.867)\cdot 17.90=(5.53+I_o')\cdot 22.62

I_0'=1.397\times 0.791

I_0'=5.851

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2\times 1.5\times (r')^2=0.321

r'^2=0.107009

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