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Taya2010 [7]
3 years ago
15

if we add mass to a paper airplane then the distance of the paper airplane will increase or decrease why?

Chemistry
2 answers:
Shalnov [3]3 years ago
8 0
Uhuhuhuhuhuhuuhuhuhuhuhuhuuhuh
puteri [66]3 years ago
8 0
You would have to test this theory
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In an experiment, a student made a compund of sulfur and copper, and now she needs to find if the compound is copper (I) sulfide
finlep [7]

<u>Answer:</u> The formula for the given compound is Cu_2S

<u>Explanation:</u>

An ionic compound is defined as the compound which is formed when electron gets transferred from one atom to another atom. These are usually formed when a metal reacts with a non-metal.

The chemical formula of copper (I) sulfide is Cu_2S because this is formed by the combination of Cu^+ ions and S^{2-} ions

The chemical formula of copper (II) sulfide is CuS because this is formed by the combination of Cu^{2+} ions and S^{2-} ions

To calculate the percent composition of element in a compound, we use the equation:

\text{Percent composition of element}=\frac{\text{Mass of element}}{\text{Mass of compound}}\times 100       ...........(1)

  • <u>For copper (I) sulfide:</u>

Mass of copper = (2 × 63.546) = 127.092 g/mol

Mass of copper (I) sulfide = 159.16 g/mol

Putting values in equation 1, we get:

\text{Percent composition of copper in }Cu_2S=\frac{127.092g}{159.16g}=79.85\%

  • <u>For copper (II) sulfide:</u>

Mass of copper = 63.546 g/mol

Mass of copper (II) sulfide = 95.611 g/mol

Putting values in equation 1, we get:

\text{Percent composition of copper in CuS}=\frac{63.546g}{95.611g}=66.46\%

  • <u>Given compound:</u>

Mass of copper in given compound = 0.8383 grams

Mass of given compound = 1.0440 grams

Putting values in equation 1, we get:

\text{Percent composition of copper in given compound}=\frac{0.8383g}{1.044g}=80.29\%

The percent composition of copper is close to the composition in copper (I) sulfide.

Hence, the formula for the given compound is Cu_2S

8 0
3 years ago
Which statement accurately compares the trends in atomic number and atomic mass in the periodic table?
Kruka [31]

Answer : The correct option is, (C) Both the atomic mass and the atomic number increase from left to right.

Explanation :

The general trend of atomic number and atomic mass in the periodic table is,

Both atomic number and atomic mass increase from left to right and decreases from right to left in the periodic table due to the addition of the number of neutrons and the number of protons in the nucleus.

Hence, the correct option is, (C) Both the atomic mass and the atomic number increase from left to right.

7 0
4 years ago
Read 2 more answers
A voltaic cell that uses the reaction PdCl2−4(aq)+Cd(s)→Pd(s)+4Cl−(aq)+Cd2+(aq) has a measured standard cell potential of +1.03
Ghella [55]

Answer : The balanced two-half reactions will be,

Oxidation half reaction : Cd(s)\rightarrow Cd^{2+}(aq)+2e^-

Reduction half reaction : Pd^{2+}(aq)+2e^-\rightarrow Pd(s)

Explanation :

Voltaic cell : It is defined as a device which is used for the conversion of the chemical energy produces in a redox reaction into the electrical energy. It is also known as the galvanic cell or electrochemical cell.

In the voltaic cell, the oxidation occurs at an anode which is a negative electrode and the reduction occurs at the cathode which is a positive electrode.

The given redox reaction is:

PdCl_4^{2-}(aq)+Cd(s)\rightarrow Pd(s)+4Cl^-(aq)+Cd^{2+}(aq)

The balanced two-half reactions will be,

Oxidation half reaction : Cd(s)\rightarrow Cd^{2+}(aq)+2e^-

Reduction half reaction : Pd^{2+}(aq)+2e^-\rightarrow Pd(s)

7 0
3 years ago
ILL GIVE YOU BRAINLIEST!!!!Which of the following is an example of a description of climate? *
Murrr4er [49]

Answer:

The relative humidity in Raleigh, NC

You can search it up online. Search up what is climate change and it will give you "the weather conditions prevailing in an area in general or over a long period." (On bing)

Explanation:

Can I have brainliest? It would help me out, if not thanks anyways! Hope this helped and have a nice day!

6 0
3 years ago
What is the freezing point (°C) of a solution prepared by dissolving 11.3 g of Ca(NO3)2 (formula weight = 164 g/mol) in 115 g of
Citrus2011 [14]

Answer:

freezing point   (°C) of the solution =  - 3.34° C

Explanation:

From the given information:

The freezing point (°C) of a solution can be prepared by using the formula:

\Delta T = iK_fm

where;

i = vant Hoff factor

the vant Hoff factor is the totality of the number of ions in the solution

Since there are 1 calcium ion and 2 nitrate ions present in Ca(NO3)2, the vant Hoff factor = 3  

K_f = 1.86 °C/m

m = molality of the solution and it can be determined by using the formula

molality = \dfrac{mole \ of \ solute }{kg \ of \ solvent }

which can now be re-written as :

molality = \dfrac{mole \ of \ Ca(NO_3)_2}{kg \ of \  water}

molality = \dfrac{\dfrac{mass \ of \  \ Ca(NO_3)_2}{molar \  mass of \ Ca(NO_3)_2} }{kg \ of \  water}

molality = \dfrac{\dfrac{11.3 \ g }{164 \ g/mol} }{0.115 \ kg }

molality = 0.599 m

∴

The freezing point (°C) of a solution can be prepared by using the formula:

\Delta T = iK_fm

\Delta T =3 \times (1.86 \ ^0C/m) \times (0.599 \ m)

\Delta T =3.34^0 \ C

\Delta T = the freezing point of water - freezing point of the solution

3.34° C = 0° C -  freezing point of the solution

freezing point  (°C) of the solution =  0° C - 3.34° C

freezing point   (°C) of the solution =  - 3.34° C

3 0
3 years ago
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