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AlekseyPX
3 years ago
12

Of the following, the greatest advantage of a database architecture is that

Computers and Technology
1 answer:
Zina [86]3 years ago
3 0

Answer:

c.

Explanation:

Of the following, the greatest advantage of a database architecture is that data redundancy can be reduced. This refers to data being unintentionally repeated within the database causing space to be taken up unnecessarily. Database architecture allows for this problem to be addressed and prevented.

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Letter Frequency Write a function that will take a string and return a count of each letter in the string. For example, "my dog
Nostrana [21]

Answer:

Check the explanation

Explanation:

Code to copy:

// ConsoleApplication7.cpp : Defines the entry point for the console application.

//

#include "stdafx.h"

#include <iostream>

#include <cstring>

#include <string>

using namespace std;

int * letterFrequency(char s[]);

int main()

{

  int *freq_letters;

  char *s = new char[100];

  freq_letters = new int[26];

  //To read the input string in order to find the frequency of each letter

  cout << "Enter a string: ";

  cin.getline(s, ' ');

  //call the function to find the occurrence of each alphabet

  freq_letters = letterFrequency(s);

  //Display the count

  cout << "Letter Frequency " << endl;

  for (int i = 0; i < 26; i++)

  {

      //Constriant to check if the letter appeared at least once in the string and so printing the frequency of its occurence

      if (freq_letters[i] != 0)

      cout << " " << static_cast<char>(i + 'a') << " " << freq_letters[i] << endl;

  }

  system("pause");

  return 0;

}

//Define the function to find occurrence of each letter in the input string

int * letterFrequency(char s[])

{

  int *occurrence_array;

//to store the output of occurrences for each alphabet

  occurrence_array = new int[26];

// to store the count of occurrence for each letter temporarily

  int letter_count;

  // for loop to check the occurrence for all 26 alphabets

 

  for (int i = 0; i < 26; i++)

  {

      letter_count = 0;

      for (int j = 0; j < strlen(s); j++)

      {

          /*comparing the ascii values of each alphabet with every character from the string by converting it to lower case i.e. case insensitive*/

          if (int('a') + i == int(tolower(s[j])))

              letter_count++;

      }

      occurrence_array[i] = letter_count;//To store the count calculated for each alphabet

  }

  return occurrence_array;

}

The following below code screenshot and output shows that when the string is entered, the output will shows each lettercount irrespective of whether the letter is in capitals or small and does not count non-letter characters (i.e spaces, punctuations etc.)

6 0
4 years ago
How do i use a computer (i'm 99999 years old)
AlekseyPX

Answer:

grandma?

Explanation:

is it you?

6 0
3 years ago
Read 2 more answers
What is a biometric scanner?
Lisa [10]
<span>an electronic device used to determine a person's identity by detecting and matching the person's physical features, such as fingerprints or the eyes, to a database</span>
3 0
3 years ago
Read 2 more answers
4. What is the connection between productivity and Microsoft Office/ Office 365?
ikadub [295]
Microsoft 365 plans for home and personal include the robust Office desktop apps that you're familiar with, like Word, PowerPoint, and Excel. ... Office 2019 is sold as a one-time purchase, which means you pay a single, up-front cost to get Office apps for one computer.

Hope this helps :)
3 0
3 years ago
What is the simplest way to convert a decimal number in a binar one in c++?
Fiesta28 [93]
It's easy you need to use function for decimal in binary.
binary STD;
int STD_no;
STD=STD_No.ToBinary

4 0
3 years ago
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