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oksano4ka [1.4K]
3 years ago
6

What is the equation of the line which

Mathematics
1 answer:
natka813 [3]3 years ago
5 0

Answer:

The equation of the line is y = (-1/2)x + 5

Step-by-step explanation:

m =  \frac{y2 - y1}{x2 - x1 }

First of all, have to find gradient using the formula above :

(2,4) & (14,-2)

m = (-2-4) / (14-2)

= -6 / 12

= -1/2

Second, using y = mx + b as b is a constant and is a y-intercept. Using any of these 2 coordinates to find the value of b with given gradient :

y = mx + b

Let y=4 & x=2

4 = (-1/2)(2) + b

b = 4 + 1

= 5

Lastly, put the value of gradient and y-intercept into the equation :

y = mx + b

Let m=-1/2 & b=5

y = (-1/2)x + 5

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Answer:

The formula to calculate the Celsius temperature for a given Fahrenheit temperature is:

C=\frac{F-32}{1.8}

Step-by-step explanation:

Given formula:

F=1.8C+32

where F represents temperature in Fahrenheit and C represents  temperature in Celsius.

To solve the equation for C.

Solution:

We have,

F=1.8C+32

Subtracting both sides by 32.

F-32=1.8C+32-32

F-32=1.8C

Dividing both side by 1.8

\frac{F-32}{1.8}=\frac{1.8C}{1.8}

\frac{F-32}{1.8}=C

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Using the above formula, we can calculate the Celsius temperature for a given Fahrenheit temperature.

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3 years ago
How write 89,170,326 in expanded and
evablogger [386]

80,000,000+9,000,000+100,000+70,000+300+20+6

8 0
3 years ago
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Solve 5x^2+2x=1 using either factoring, square root method, completing the square or quadratic formula.
wolverine [178]

Answer:

x = -1 ± √6 / 5

Step-by-step explanation:

Solve 5x^{2} + 2x = 1

move 1 to the left side of the equation by subtracting it from both sides.

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Use the quadratic formula to find the solutions.

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Simplify.

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Exact Form:

x = -1 ± \sqrt{6}/ 5

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Peggy earned $20 for each lawn she mowed last summer. This summer, she raised her price to $23 per lawn. What is the percent inc
anyanavicka [17]

Answer:

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23-20

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Why does a calculator return an error when trying to find inverse sine of 1.055?
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The calculator returns an error as the answer for the inverse sine of 1.055 because the acceptable range for sine is only from 0 to 1.00 in which 1.055 is clearly greater than. This is also the same as for the cosine values. 
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