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patriot [66]
2 years ago
9

The biggest bowl of mashed potatoes ever made weighed 4.56 x 10^4 pounds and

Mathematics
1 answer:
Bess [88]2 years ago
6 0

We have been given that the biggest bowl of mashed potatoes ever made weighed 4.5\times 10^4 pounds and  was created at the Iowo State Fair in 2005. The biggest deep dish pizza ever  made was in Chicago in 1998. It weighed a whopping 1.23\times 10^5 pounds.

To find how much pizza weighs more than bowl of mashed potatoes, we will subtract weight of mashed potatoes from weight of pizza.

1.23\times 10^5-4.56\times 10^4

1.23\times 100000-4.56\times 10000

123000-45600=77400

Now we will convert 77400 into scientific notation as:

77400=7.74\times 10^4

Therefore, the pizza weighs 77400=7.74\times 10^4 pounds more than the bowl of mashed potatoes.

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Put the differential equation 9ty+ety′=yt2+81 into the form y′+p(t)y=g(t) and find p(t) and g(t). p(t)= help (formulas) g(t)= he
alexgriva [62]

Answer:

p(t) = \frac{9t^{3} + 729t  - 1}{e^{t}(t^{2} + 81) }

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And

The differential equation 9ty + e^{t}y' = \frac{y}{t^{2} + 81 } is  linear and homogeneous

Step-by-step explanation:

Given that,

The differential equation is -

9ty + e^{t}y' = \frac{y}{t^{2} + 81 }

e^{t}y' + (9t - \frac{1}{t^{2} + 81 } )y = 0\\e^{t}y' + (\frac{9t(t^{2} + 81 ) - 1}{t^{2} + 81 } )y = 0\\e^{t}y' + (\frac{9t^{3} + 729t  - 1}{t^{2} + 81 } )y = 0\\y' + [\frac{9t^{3} + 729t  - 1}{e^{t}(t^{2} + 81) } ]y = 0

By comparing with y′+p(t)y=g(t), we get

p(t) = \frac{9t^{3} + 729t  - 1}{e^{t}(t^{2} + 81) }

g(t) = 0

And

The differential equation 9ty + e^{t}y' = \frac{y}{t^{2} + 81 } is  linear and homogeneous.

6 0
2 years ago
Please help i really don't understand ​
Bezzdna [24]

Answer:

3.75

Step-by-step explanation:

That is the decimal

7 0
2 years ago
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Answer:

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Alternative hypothesis : H1 : p ≠ 0.47

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percentage favoring construction of adjoining community = 47%

level = 0.05

To determine if the 0.05 confidence level is enough to support the major's claim we have to state the Null and alternative hypothesis

Null hypothesis ; H0 : p = 0.47

Alternative hypothesis : H1 : p ≠ 0.47

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Answer:

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