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patriot [66]
3 years ago
9

The biggest bowl of mashed potatoes ever made weighed 4.56 x 10^4 pounds and

Mathematics
1 answer:
Bess [88]3 years ago
6 0

We have been given that the biggest bowl of mashed potatoes ever made weighed 4.5\times 10^4 pounds and  was created at the Iowo State Fair in 2005. The biggest deep dish pizza ever  made was in Chicago in 1998. It weighed a whopping 1.23\times 10^5 pounds.

To find how much pizza weighs more than bowl of mashed potatoes, we will subtract weight of mashed potatoes from weight of pizza.

1.23\times 10^5-4.56\times 10^4

1.23\times 100000-4.56\times 10000

123000-45600=77400

Now we will convert 77400 into scientific notation as:

77400=7.74\times 10^4

Therefore, the pizza weighs 77400=7.74\times 10^4 pounds more than the bowl of mashed potatoes.

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A hollow metal sphere has 6 cm inner and 8cm outer radii. The surface charge densities on the exterior surface is +100 nC/m2 and
natulia [17]

Answer:

<h2>Outer Electric Field is 11250 N/C.</h2><h2>Inner Electric Field is -10000 N/C.</h2>

Step-by-step explanation:

First of all, we need to read carefully and analyse the problem. As you can see, is an electrical subject, and it's given surface charge densities and radius.

So, to calculate electric fields, we need to find the proper equation to do so: E=k\frac{q}{r^{2} }; as you can see, first we need to find the charges.

We can find all charges using the surface charge densities, because it has the next relation: p=\frac{q}{A}; which indicates that charge density is the amount of charge per area. But, there's a problem, we don't have areas, so we have to calculate them first with this relation: S=4\pi r^{2}; which gives us the surface of a sphere.

The inner surface: Si=4\pi (0.06m)^{2} = 0.04 m^{2}

The outer surface: S=4\pi (0.08m)^{2}=0.08m^{2}

Now we can calculate the charges,

Inner charge: Qi=pA=(-100\frac{nC}{m^{2} } )(0.04m^{2} )=-4nC

Outer charge: Qo=pA=100\frac{nC}{m^{2} } )(0.08m^{2} )=8nC

Then, we are able to calculate both fields:

Inner field: Ei=k\frac{Qi}{r^{2} }=9x10^{9} \frac{Nm^{2} }{C^{2} }\frac{-4x10^{-9} }{0.06m^{2} }=-10000\frac{N}{C}

Outer field:  Eo=k\frac{Qo}{r^{2} }=9x10^{9} \frac{Nm^{2} }{C^{2} }\frac{8x10^{-9} }{0.08m^{2} }=11250\frac{N}{C}

The directions that field have is opposite each other, the inner one has an inside direction, and the outer electric field has an outside direction.

3 0
3 years ago
Please help me !!!!!!
Nezavi [6.7K]

Answer:

A

Step-by-step explanation:

Hope it helps!

5 0
3 years ago
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Which number is a factor of 14 but not a multiple of 2
GalinKa [24]
A factor of 14 is 7, and it isnt a multiple of 2.

7 x 2 = 14
6 0
3 years ago
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Which point lies on the line with point-slope equation y-3=4(x+7)
Arte-miy333 [17]

Point slope equation for point (h,k) and slope m is given by

y-k=m(x-h)

compare given equation with formula

we get h=-7, k=3

so the required point is (-7,3)

7 0
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Grade 9 math plzz helpp a or b or c or d
hram777 [196]

Answer:

g(x) = 3^{x -4}

Step-by-step explanation:

Given

f(x) = 3^x

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Required

Find g(x)

When a point is translated 4 units left, the rule is:

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So, we have:

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f(x-4) is calculated as:

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Hence:

g(x) = 3^{x -4}

4 0
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