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velikii [3]
3 years ago
13

PLEASE HELP ASAP!!

Mathematics
1 answer:
Katarina [22]3 years ago
8 0

<u>Solutions:</u>

<u>Part A:</u>

Let y_{1}=(4-x) \text { and } y_{2}=(2-x+1)

As we know that the values at the point of intersection are the values that satisfy both the equation at that particular point.

So at insertion point, y_{1}=y_{2}

Hence (4-x)=(2-x+1)

<u>Part 2: </u>

The problem asked to make tables to find the solution to 4-x=2-x+1

If we take the first equation,

y=4-x

then, the table for (x,y) is (-2,6), (-1,5), (0,4), (1,3), (2,2), (3,1), (4,0)

if we take the second equation,

y=2-x+1

then the table for (x,y) is(-2,5),(-1,4), (0,3), (1,2), (2,1), (3,0), (4,-1)

<u>Part 3: </u>

We can solve the equation 4-x = 2-x+1 graphically by drawing the line y = 4-x and y= 2-x+1 in the graph. The intersecting point of both the lines will be the solution.

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