Question

PLEASE HELP ASAP!!

Answer 1

Solutions:

Part A:

Let $y_{1}=(4-x) \text { and } y_{2}=(2-x+1)$

As we know that the values at the point of intersection are the values that satisfy both the equation at that particular point.

So at insertion point, $y_{1}=y_{2}$

Hence $(4-x)=(2-x+1)$

Part 2:

The problem asked to make tables to find the solution to $4-x=2-x+1$

If we take the first equation,

$y=4-x$

then, the table for (x,y) is $(-2,6), (-1,5), (0,4), (1,3), (2,2), (3,1), (4,0)$

if we take the second equation,

$y=2-x+1$

then the table for (x,y) is$(-2,5),(-1,4), (0,3), (1,2), (2,1), (3,0), (4,-1)$

Part 3:

We can solve the equation $4-x = 2-x+1$ graphically by drawing the line $y = 4-x$ and $y= 2-x+1$ in the graph. The intersecting point of both the lines will be the solution.