Hey there!
2 + 89 = 91,
so x = 2
Hope this helps!
Have a great day (:
Answer:
Step-by-step explanation:
Given z = x+iy
The polar form of a complex number 
The nth root of the complex number is expressed according to de moivre's theorem as;
![z^{\frac{1}{n} } = [r(cos\theta + isin\theta)]^{\frac{1}{n} } \\z^{\frac{1}{n} } = \sqrt[n]{r} (cos(\frac{\theta+2nk}{n} ) + isin(\frac{\theta+2nk}{n}))](https://tex.z-dn.net/?f=z%5E%7B%5Cfrac%7B1%7D%7Bn%7D%20%7D%20%20%3D%20%5Br%28cos%5Ctheta%20%2B%20isin%5Ctheta%29%5D%5E%7B%5Cfrac%7B1%7D%7Bn%7D%20%7D%20%5C%5Cz%5E%7B%5Cfrac%7B1%7D%7Bn%7D%20%7D%20%3D%20%5Csqrt%5Bn%5D%7Br%7D%20%28cos%28%5Cfrac%7B%5Ctheta%2B2nk%7D%7Bn%7D%20%29%20%2B%20isin%28%5Cfrac%7B%5Ctheta%2B2nk%7D%7Bn%7D%29%29)
r is the modulus of the complex number and
is the argument
r = √x²+y²

Given z = -9i
r = √0+(-9)²
r = √81
r = 9

The argument will be equivalent to 180-90 = 90°
The forth root of -9i will be expressed as shown according to de moivre's theorem;
![z_k^{\frac{1}{4} } = \sqrt[4]{9} (cos(\frac{90+2(4)k}{4} ) + isin(\frac{90+2(4)k}{4}))\\z_k^{\frac{1}{4} } = \sqrt[4]{9} (cos(\frac{90+8k}{4} ) + isin(\frac{90+8k}{4}))\\](https://tex.z-dn.net/?f=z_k%5E%7B%5Cfrac%7B1%7D%7B4%7D%20%7D%20%3D%20%5Csqrt%5B4%5D%7B9%7D%20%20%28cos%28%5Cfrac%7B90%2B2%284%29k%7D%7B4%7D%20%29%20%2B%20isin%28%5Cfrac%7B90%2B2%284%29k%7D%7B4%7D%29%29%5C%5Cz_k%5E%7B%5Cfrac%7B1%7D%7B4%7D%20%7D%20%3D%20%5Csqrt%5B4%5D%7B9%7D%20%20%28cos%28%5Cfrac%7B90%2B8k%7D%7B4%7D%20%29%20%2B%20isin%28%5Cfrac%7B90%2B8k%7D%7B4%7D%29%29%5C%5C)
The complex roots are at when k = 0, 1, 2 and 3
When k = 0;
![z_0 = \sqrt[4]{9} (cos(\frac{90}{4} ) + isin(\frac{90}{4}))\\z_0 = \sqrt[4]{9} (cos(23) + isin(23))\\\\when\ k =1\\z_1 = \sqrt[4]{9} (cos(\frac{90+8}{4} ) + isin(\frac{90+8}{4}))\\z_1 = \sqrt[4]{9} (cos(25 ) + isin(25))\\\\when\ k =2\\z_2 = \sqrt[4]{9} (cos(\frac{90+16}{4} ) + isin(\frac{90+16}{4}))\\z_2 = \sqrt[4]{9} (cos(27 ) + isin(27))\\\\when\ k =3\\z_3 = \sqrt[4]{9} (cos(\frac{90+24}{4} ) + isin(\frac{90+24}{4}))\\z_3 = \sqrt[4]{9} (cos(29 ) + isin(29))\\](https://tex.z-dn.net/?f=z_0%20%3D%20%5Csqrt%5B4%5D%7B9%7D%20%20%28cos%28%5Cfrac%7B90%7D%7B4%7D%20%29%20%2B%20isin%28%5Cfrac%7B90%7D%7B4%7D%29%29%5C%5Cz_0%20%3D%20%5Csqrt%5B4%5D%7B9%7D%20%20%28cos%2823%29%20%2B%20isin%2823%29%29%5C%5C%5C%5Cwhen%5C%20k%20%3D1%5C%5Cz_1%20%3D%20%5Csqrt%5B4%5D%7B9%7D%20%20%28cos%28%5Cfrac%7B90%2B8%7D%7B4%7D%20%29%20%2B%20isin%28%5Cfrac%7B90%2B8%7D%7B4%7D%29%29%5C%5Cz_1%20%3D%20%5Csqrt%5B4%5D%7B9%7D%20%20%28cos%2825%20%29%20%2B%20isin%2825%29%29%5C%5C%5C%5Cwhen%5C%20k%20%3D2%5C%5Cz_2%20%3D%20%5Csqrt%5B4%5D%7B9%7D%20%20%28cos%28%5Cfrac%7B90%2B16%7D%7B4%7D%20%29%20%2B%20isin%28%5Cfrac%7B90%2B16%7D%7B4%7D%29%29%5C%5Cz_2%20%3D%20%5Csqrt%5B4%5D%7B9%7D%20%20%28cos%2827%20%29%20%2B%20isin%2827%29%29%5C%5C%5C%5Cwhen%5C%20k%20%3D3%5C%5Cz_3%20%3D%20%5Csqrt%5B4%5D%7B9%7D%20%20%28cos%28%5Cfrac%7B90%2B24%7D%7B4%7D%20%29%20%2B%20isin%28%5Cfrac%7B90%2B24%7D%7B4%7D%29%29%5C%5Cz_3%20%3D%20%5Csqrt%5B4%5D%7B9%7D%20%20%28cos%2829%20%29%20%2B%20isin%2829%29%29%5C%5C)
Note that all the degrees are rounded to the nearest whole number.
Answer: The standard error of the sample mean = 0.44
Step-by-step explanation:
Standard error of the sample mean =
<em> , where </em>
= population standard deviation , n= sample size.
Given : n= 45 ,
grams
The e standard error of the sample mean 

Hence, the standard error of the sample mean = 0.44
First, you must do the parentheses!!!
Next, when you are done solving the parentheses, you will do the outside numbers!!
Then, when doing the outside numbers, you'll combine(doing +, ×, ÷ or -)
And finally, you get your answer!!!
:):):):):)
Well, you know that the area of the rectangle is 12 square feet. And you know one of the numbers multiplied to get 12 is 5, so divide 12 by 5. You would get 2.4 as the other number needed.
In this case, 5 feet is the width and 2.4 feet is the length.