Answer: The initial temperature was 263 K
Explanation:
Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.
The combined gas equation is,
![\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}](https://tex.z-dn.net/?f=%5Cfrac%7BP_1V_1%7D%7BT_1%7D%3D%5Cfrac%7BP_2V_2%7D%7BT_2%7D)
where,
= initial pressure of gas = 0.939 atm
= final pressure of gas = 1.00 atm
= initial volume of gas = 9.40 L
= final volume of gas = 10.0 L
= initial temperature of gas = ?
= final temperature of gas = ![25^oC=273+25=298K](https://tex.z-dn.net/?f=25%5EoC%3D273%2B25%3D298K)
Now put all the given values in the above equation, we get:
![\frac{0.939\times 9.40}{T_1}=\frac{1.00\times 10.0}{298}](https://tex.z-dn.net/?f=%5Cfrac%7B0.939%5Ctimes%209.40%7D%7BT_1%7D%3D%5Cfrac%7B1.00%5Ctimes%2010.0%7D%7B298%7D)
![T_1=263K](https://tex.z-dn.net/?f=T_1%3D263K)
Thus the initial temperature was 263 K