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natta225 [31]
3 years ago
14

Plzzzzzz help me Write electronic configuratof sodium and chlorine in the term of subshell ?

Chemistry
2 answers:
Ber [7]3 years ago
6 0

Answer:

ans:Ne=2,8,1

ans:2,8,7

nalin [4]3 years ago
5 0

Ok Thank u for the information

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How many moles of water are produced from 373 mol Al??
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Natalka [10]

Answer: (a) Mole fraction of H_{2} is 0.66.

Mole fraction of N_{2} is 0.33

(b) The partial pressure of H_{2} is 1.98 atm.

The partial pressure of N_{2} is 0.99 atm.

(c) The total pressure is 3.0 atm

Explanation:

Given: Volume = 22.4 dm^{3}  (1 dm^{3} = 1 L) = 22.4 L

Moles of H_{2} = 2.0 mol

Moles of N_{2} = 1.0 mol

Total moles = (2.0 + 1.0) mol = 3.0 mol

Temperature = 273.15 K

  • Now, using ideal gas equation the total pressure is calculated as follows.

PV = nRT\\

where,

P = pressure

V = volume

n = number of moles

R = gas constant = 0.0821 L atm/mol K

T = temperature

Substitute the values into above formula as follows.

PV = nRT\\P \times 22.4 L = 3.0 mol \times 0.0821 L atm/mol K \times 273.15 K\\P = 3.0 atm

  • The mole fractions of each component:

The mole fraction of H_{2} is calculated as follows.

Mole fraction = \frac{moles of H_{2}}{moles of H_{2} + moles of N_{2}}\\= \frac{2.0 mol}{(2.0 + 1.0) mol}\\= 0.66

The mole fraction of N_{2} is as follows.

Mole fraction = \frac{moles of N_{2}}{moles of H_{2} + moles of N_{2}}\\= \frac{1.0 mol}{(2.0 + 1.0) mol}\\= 0.33

  • The partial pressures of each component:

Partial pressure of H_{2} are as follows.

P_{H_{2}} = P_{total} \times mole fraction of H_{2}\\= 3.0 atm \times 0.66\\= 1.98 atm

Partial pressure of N_{2} are as follows.

P_{N_{2}} = P_{total} \times mola fraction of N_{2}\\= 3.0 atm \times 0.33\\= 0.99 atm

7 0
3 years ago
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