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DanielleElmas [232]
3 years ago
8

If 17.8 grams of KOH dissolve in enough water to make a 198-gram solution, what is the concentration in percent by mass?

Chemistry
1 answer:
sleet_krkn [62]3 years ago
7 0
Solute of solution = 17.8 g

Solvn = 198 g

% = 17.8 / 198

w% = 0.089 x 100 = 8.9%  by mass

hope this helps!
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neonofarm [45]

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The answer to your question is 0.10 M

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Data

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Formula

Molarity = moles / volume

Process

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C₁₂H₂₂O₁₁ = (12 x 12) + (1 x 22) + (16 x 11)

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                  342 g of sucrose ------------------- 1 mol

                  125 g of sucrose -------------------- x

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