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SIZIF [17.4K]
3 years ago
14

A trampolinist steps off from 15 feet above ground to a trampoline 13 feet below. The function h (t) = -16 t 2 + 15, where t rep

resents the time in seconds, gives the height h, in feet, of the trampolinist above the ground as he falls. When will the trampolinist land on the trampoline?
Mathematics
1 answer:
kondor19780726 [428]3 years ago
5 0

Answer:

Trampolinist will land on the trampoline after 0.9 seconds.

Step-by-step explanation:

The function h(t) = -16t² + 15 represents the relation between height 'h' above the ground and the time 't' of the trampolinist.

We have to find the time when trampolinist lands on the ground.

That means we have to find the value of 't' when h(t) = 15 - 13 = 2

[Since trampoline is 2 feet above the ground]

When we plug in the value h(t) = 2

2 = -16t² + 15

2 + 16t² = -16t² + 16t² + 15

16t² + 2 = 15

16t² + 2 - 2 = 15 - 2

16t² = 13

\frac{16t^{2}}{16}=\frac{13}{16}

t^{2}=\frac{13}{16}

t = \sqrt{\frac{13}{16}}

t ≈ 0.9 seconds

Therefore, trampolinist will land on the trampoline at 0.9 seconds.

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If a fair coin is tossed 6 times, what is the probability, to the nearest thousandth, of getting exactly 6 tails?
xxTIMURxx [149]
<h2>Answer:</h2>

\frac{1}{64}

<h2>Step-by-step explanation:</h2>

The\ probability\ of\ tails\ per\ flip\ is\ \frac{1}{2}

so\ the\ probability\ of\ getting\ six

tails\ is

\frac{1}{2}\times\frac{1}{2}\times\frac{1}{2}\times\frac{1}{2}\times\frac{1}{2}\times\frac{1}{2}=\frac{1}{64}

The\ probability\ of\ getting\ tails\ every

time\ you\ multiply\ them\ is\ the

probobility\ of\ getting\ tails\ all\ six

times?

<em>I hope this helps you</em>

<em>:)</em>

3 0
2 years ago
The length of a rectangle field is represented by the expression 14 X minus 3X squared +2 Y. The width of the field is represent
Assoli18 [71]

Answer:

9x+4x^2-5y

Step-by-step explanation:

Hi there!

Length of the field: 14x-3x^2+2y units

Width of the field: 5x-7x^2+7y units

To find how much greater the length of the field is than the width, subtract the width from the length:

14x-3x^2+2y-(5x-7x^2+7y)

Open up the parentheses

= 14x-3x^2+2y-5x+7x^2-7y

Combine like terms

= 14x-5x-3x^2+7x^2+2y-7y\\= 9x+4x^2-5y

Therefore, the length is 9x+4x^2-5y units greater than the width.

I hope this helps!

7 0
2 years ago
What is the answer for the picture that is linked below?
____ [38]

Answer:

18%

Step-by-step explanation:

6840:38000*100 =

(6840*100):38000 =

684000:38000 = 18

3 0
3 years ago
PLSSSSS HELP I BEG YOU I WILL GIVE BRAINLIEST WHOEVER ANSWERS FIRAT AND CORRECT.!!!
geniusboy [140]

Answer:

WHASTW THE QUESTION?

Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
A plane flew 360km in 3 hrs when flying with the wind.With no change in the wind,the return trip took 4 hrs.Find the speed of th
morpeh [17]
Speed of the plane: 250 mph
Speed of the wind: 50 mph
Explanation:
Let p = the speed of the plane
and w = the speed of the wind
It takes the plane 3 hours to go 600 miles when against the headwind and 2 hours to go 600 miles with the headwind. So we set up a system of equations.
600
m
i
3
h
r
=
p
−
w
600
m
i
2
h
r
=
p
+
w
Solving for the left sides we get:
200mph = p - w
300mph = p + w
Now solve for one variable in either equation. I'll solve for x in the first equation:
200mph = p - w
Add w to both sides:
p = 200mph + w
Now we can substitute the x that we found in the first equation into the second equation so we can solve for w:
300mph = (200mph + w) + w
Combine like terms:
300mph = 200mph + 2w
Subtract 200mph on both sides:
100mph = 2w
Divide by 2:
50mph = w
So the speed of the wind is 50mph.
Now plug the value we just found back in to either equation to find the speed of the plane, I'll plug it into the first equation:
200mph = p - 50mph
Add 50mph on both sides:
250mph = p
So the speed of the plane in still air is 250mph.
6 0
3 years ago
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