#7
d/2 +d/5 + d/3 = 3
(15d + 6d + 10d) / 30 = 3
15d + 6d + 10d = 90
31d = 90
d = 90/31
d = 2 28/31
Answer:

Step-by-step explanation:
<u>Roots of a polynomial</u>
If we know the roots of a polynomial, say x1,x2,x3,...,xn, we can construct the polynomial using the formula

Where a is an arbitrary constant.
We know three of the roots of the degree-5 polynomial are:

We can complete the two remaining roots by knowing the complex roots in a polynomial with real coefficients, always come paired with their conjugates. This means that the fourth and fifth roots are:

Let's build up the polynomial, assuming a=1:

Since:


Operating the last two factors:

Operating, we have the required polynomial:

Answer:
7 and 9
Step-by-step explanation:
4/3÷1/6 = 4/3 × 6/1
= 8
So the value of p falls between the range of 7 and 9
Answer:
x = 
Step-by-step explanation:
Let the number be x.

x - 3 = 10x
9x = -3
x = 
Cube root of 8=2 so the fraction simplifies to 2/27 (in decimal form it’s .074 repeating)