1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
mestny [16]
3 years ago
8

Sometimes when you are adding, you can breack apart ones to make a ten 37+8=?

Mathematics
2 answers:
IRINA_888 [86]3 years ago
8 0

37+8=45

You can also break it into tens and ones:

30+7+1+1+1+1+1+1+1+1

30+7=37

1+1+1+1+1+1+1+1=8

37+8=45

kipiarov [429]3 years ago
7 0
30+7+1+1+1+1+1+1+1+1=
45
You might be interested in
Log10^x - log10^3 - 1
Pavel [41]

Answer:

1^x-2

Step-by-step explanation:

First you put log(10)^x into the calculator, the product is 1^x. Then you subtract that by log(10)^3 which you you get 1^x-1 then you subtract that answer by 1 to get 1^x-2.

8 0
3 years ago
1/8(-8c +16) - 1/3(6+3c)
Bess [88]

Answer:

-2c

Step-by-step explanation:

5 0
3 years ago
A gumball has a diameter that is 66 mm. The diameter of the gumball's spherical hollow core is 58 mm. What is the volume of the
grigory [225]

Answer:

Volume of gumball without including its hollow core is 48347.6 cubic mm.

Step-by-step explanation:

Given:

Diameter of Gumball = 66 mm

Since radius is half of diameter.

Radius of gumball = \frac{diameter}{2}=\frac{66}{2} =33 \ mm

Now We will first find the Volume of Gumball.

To find the Volume of Gumball we will use volume of sphere which is given as;

Volume of Sphere = \frac{4}{3}\pi r^3

Now Volume of Gumball = \frac{4}{3}\times3.14 \times (33)^3 = 150456.24 \ mm^3

Also Given

Diameter of gumball's spherical hollow core = 58 mm

Since radius is half of diameter.

Radius of gumball's spherical hollow core = \frac{diameter}{2}=\frac{58}{2} =29 \ mm

Now We will find the Volume of gumball's spherical hollow core.

Volume of Sphere = \frac{4}{3}\pi r^3

So Volume of gumball's spherical hollow core = \frac{4}{3}\times3.14 \times (29)^3 = 102108.61 \ mm^3

Now We need to find volume of the gumball without including its hollow core.

So, To find volume of the gumball without including its hollow core we would Subtract Volume of gumball spherical hollow core from Volume of Gumball.

volume of the gumball without including its hollow core = Volume of Gumball - Volume of gumball's spherical hollow core = 150456.24\ mm^3 - 102108.61\ mm^3 = 48347.63\ mm^3

Rounding to nearest tenth we get;

volume of the gumball without including its hollow core = 48347.6\ mm^3

Hence Volume of gumball without including its hollow core is 48347.6 cubic mm.

8 0
3 years ago
The box plots represent the birth weights, in pounds, of babies born full term at a hospital during one week.
Verdich [7]

Answer:

less than , less than, minimum

Step-by-step explanation:

got it right

8 0
2 years ago
QUESTION 6
Oxana [17]

Answer:

Option D. 17%

Step-by-step explanation:

we have

f(x)=250,000(1.17)^{x}

This is a exponential function of the form

f(x)=a(b)^{x}

where

a is the initial value

b is the base

In this problem

a=250,000 people

b=1.17

Remember that

b=1+r

so

1+r=1.17

r=1.17-1=0.17

Convert to percentage

0.17*100=17%

8 0
3 years ago
Read 2 more answers
Other questions:
  • to the nearest thousandth what is the cosine of the angle formed by the line whose equation is y=2x and the positive x axis
    14·1 answer
  • The equation of a linear function in point-slope form is y – y1 = m(x – x1). Harold correctly wrote the equation y = 3(x – 7) us
    10·1 answer
  • H(r)=−(r+9) 2 +36h, left parenthesis, r, right parenthesis, equals, minus, left parenthesis, r, plus, 9, right parenthesis, squa
    10·1 answer
  • 6-3(x-5)=5x-11 how do i do this
    13·2 answers
  • The question is in the picture
    6·1 answer
  • Need help with this question how many times will the lines intersect?
    14·1 answer
  • I NEED HELP ASAP... PLEASE HELP
    14·1 answer
  • Please. very easy! will give brainliest
    13·2 answers
  • Please help I need this​
    6·1 answer
  • A cylindrical tank whose diameter and height are 2.1m and 4m respectively is filled with water whose density is 1g/cm^3.calculat
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!