Answer:
254 in
Step-by-step explanation:
1 yard = 36 in
7 yards = 36 (7)
7 yards = 252
add 2
254 in
:)
Part A.
Ashwin had a 4-cm cube.
volume of cube = side^3
volume = (4 cm)^3 = 64 cm^3
Ashwin has 64 small cubes.
We need to find the volumes of all prisms in Part A. Only prisms with at most 64 cm^3 volume can be the answer.
A. v = 2 * 4 * 7 = 28
B. v = 4 * 5 * 6 = 120
C. v = 5 * 5 * 4 = 100
D. v = 4 * 7 * 5 = 140
E. v = 3 * 5 * 4 = 60
Part A. answer: A, E
Part B.
Dora had a 5-cm cube.
volume of cube = side^3
volume = (5 cm)^3 = 125 cm^3
Dora has 125 small cubes.
We need to find the volumes of all prisms in Part B. Only prisms with at most 125 cm^3 volume can be the answer.
A. v = 3 * 3 * 8 = 72
B. v = 3 * 4 * 5 = 60
C. v = 6 * 6 * 4 = 144
D. v = 5 * 8 * 4 = 160
E. v = 3 * 5 * 4 = 60
Part B. answer: A, B, E
Answer:
Width of the rectangular Park = 11 feet
Step-by-step explanation:
Given that the total length of the fencing is 62 feet. As has to be fenced around a rectangular park , it would be the perimeter of the rectangular park.
Also Shana wants the length of the run to be 20 feet. Hence the length of the park is 20 feet.
Here we will use the formula for perimeter to find the width of the run
Perimeter = 2(l+w)
62=2(l+w)
l+w = 
l+w=31
20+w=31
w=31-20
w=11
Hence the width of the run for her dog in park would be 11 feet.
Answer:
5 ≤ h<7
Step-by-step explanation:
the rider has to be more than at least 5 feet tall, so h is greater than or equal to 5 (5 ≤ h), but they have to be less than 7 feet tall (h<7) so, therefore, we get 5 ≤ h<7
