Answer:
We take v in the vector space V different from 0. Since v is not 0, then
Lets take k>0 such that
Now, we take any vector w. We want to show that .
Since v is any non-zero vector, then this will prove that for any vectors a,b. The reason is that for any vector different from 0, lets name it x, there will exist a constant such that for any y (this is for the same reason a constant exists for v). Since y can be anything, then it can be v. But that means that , because v also has its constant k.
Now, lets show that . Lets take a constant c such that . We have that
Thus
Which means that
Which means that . As a consequence
Which proves what we were looking for.
What we know:
.26 per ounce of crackers
1 box=10ounces
Waht we need to find:
Cost of box= $2.60
.26×10=2.60
<span>2x-5y=-6
8x+3y=68
|x y +1|
|2 -5 6| = 0
|8 3 -68|
DET = 6+40 = 46
x*DET = 340-18
x = 7
-y*DET = -136-48
y = 4
</span>
To get x by itself, you would add 13 to both sides. x=115