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Whitepunk [10]
3 years ago
6

What do I do to find the surface area of a cylinder ?

Mathematics
1 answer:
Savatey [412]3 years ago
5 0

Answer: 471.24 square cm.

Step-by-step explanation: First find the area of one circular base by using the formula \pi r^2. The radius is 5, so first square that. 5^2=25. Now multiply by pi, using 3.14 for pi.  25*3.14=78.5.

Since there are 2 circular bases, multiply the area of one base by 2. 78.5*2=157.

Now to find the surface area of the rest of it, first find the circumference of one circular base by using the formula \pi d. The diameter is the radius multiplied by 2. 5*2=10. Now multiply by pi. 10*3.14=31.4. Now multiply this by the height of the cylinder. 31.4*10=314.

Finally add up the areas of the two circular bases and the area of the rest of the cylinder. 314+157=471.

Assuming that an expanded form of pi was used by using the π button on a calculator, this answer is closest to 471.24.

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Answer:

1,536 square centimeters

Step-by-step explanation:

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lapo4ka [179]

Answer: Crashes due to pilot error is the most serious threat to aviation safety as it has highest relative frequency.

Step-by-step explanation:

Since we have given that

Number of crashes due to pilot error = 699

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Number of crashes due to mechanical problems = 156

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Total number of crashes = 699+88+156+164 = 1167

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6 0
4 years ago
Write the equation of the line perpendicular to y = 5/3x + 1 that passes through the point (- 8, 2)
xenn [34]

Answer:

y = - \frac{3}{5} x - \frac{14}{5}

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

y = \frac{5}{3} x + 1 ← is in slope- intercept form

with slope m = \frac{5}{3}

Given a line with slope m then the slope of a line perpendicular to it is

m_{perpendicular} = - \frac{1}{m} = - \frac{1}{\frac{5}{3} } = - \frac{3}{5} , thus

y = - \frac{3}{5} x + c ← is the partial equation

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2 = \frac{24}{5} + c ⇒ c = 2 - \frac{24}{5} = - \frac{14}{5}

y = - \frac{3}{5} x - \frac{14}{5} ← equation of perpendicular line

4 0
3 years ago
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