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dimulka [17.4K]
3 years ago
8

Write the equation of the line perpendicular to y = 5/3x + 1 that passes through the point (- 8, 2)

Mathematics
1 answer:
xenn [34]3 years ago
4 0

Answer:

y = - \frac{3}{5} x - \frac{14}{5}

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

y = \frac{5}{3} x + 1 ← is in slope- intercept form

with slope m = \frac{5}{3}

Given a line with slope m then the slope of a line perpendicular to it is

m_{perpendicular} = - \frac{1}{m} = - \frac{1}{\frac{5}{3} } = - \frac{3}{5} , thus

y = - \frac{3}{5} x + c ← is the partial equation

To find c substitute (- 8, 2) into the partial equation

2 = \frac{24}{5} + c ⇒ c = 2 - \frac{24}{5} = - \frac{14}{5}

y = - \frac{3}{5} x - \frac{14}{5} ← equation of perpendicular line

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3 years ago
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where the upperindex denotes the position of eah number. This gives

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that is, 365 based 7 is equal to 194 bases 10.

Now, lets do the same for 43 based x. Lets convert 43 based x to base 10:

43_x=4\times x^1+3\times x^0

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1 year ago
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