Answer:
=
−
±
2
−
4
√
2
x=\frac{-{\color{#e8710a}{b}} \pm \sqrt{{\color{#e8710a}{b}}^{2}-4{\color{#c92786}{a}}{\color{#129eaf}{c}}}}{2{\color{#c92786}{a}}}
x=2a−b±b2−4ac
Once in standard form, identify a, b, and c from the original equation and plug them into the quadratic formula.
6
2
−
5
−
4
=
0
6x^{2}-5x-4=0
6x2−5x−4=0
=
6
a={\color{#c92786}{6}}
a=6
=
−
5
b={\color{#e8710a}{-5}}
b=−5
=
−
4
c={\color{#129eaf}{-4}}
c=−4
=
−
(
−
5
)
±
(
−
5
)
2
−
4
⋅
6
(
−
4
)
√
2
⋅
6
Step-by-step explanation:
Step-by-step explanation:
I hope you have a good day
Answer:
137
Step-by-step explanation:
A straight line is 180 so take 180 and subtract 43
x - 27 = 62 → ( add 27 to both sides )
x - 27 + 27 = 62 + 27
x = 89
drag first box then box with x = 89
Answer:
x = -1 and y = 1
Step-by-step explanation:
5x + 2y = -3 . . . . . . . (i)
x + 5y = 4 . . . . . . . (ii)
- Finding x in terms of y from eq. (ii) :-
x + 5y = 4
x = 4 - 5y
- Placing this value of x in eq. (i) :-
5(4 - 5y) + 2y = -3
20 - 25y + 2y = -3
-23y = - 23
<u>y = 1</u>
- Placing the value of y in eq. (i)
5x + 2(1) = -3
5x + 2 = -3
5x = - 5
<u>x = -1</u>
