All categories

2 years ago

Write the following in correct mathematical language: 45.23

Mathematics

2 answers:

mr_godi [17]2 years ago

5 0

Forty five and twenty three hundredths.

dexar [7]2 years ago

3 0

Forty-five and twenty-three hundredths.

In general, with decimals, the first place value after the decimal is read as a tenth, the second is read as a hundredth, the third is read as a thousandth, and so on. In front of the decimal, we know that 4 is in the tens place and 5 is in the ones place, so we say forty-five. Past the decimal, 2 is in the tenths place (think about how 2/10 = .2, which is "two-tenths") and 3 is in the hundredths place (think about how 23/100 = .23). You read the number after the decimal like normal ("twenty-three," "two-hundred fifteen," etc), then you add the place ("tenths, hundredths, ten-thousands") at the very end.

You might be interested in

Asking for a fifth time:

TiliK225 [7]

Answer:

The Réaumur scale also known as the "octogesimal division", is a temperature scale in which the freezing and boiling points of water are set to 0 and 80 degrees respectively. The scale is named after René Antoine Ferchault de Réaumur, who first proposed something similar in 1730.

Fahrenheit is a thermodynamic temperature scale, where the freezing point of water is 32 degrees Fahrenheit (°F) and the boiling point 212°F (at standard atmospheric pressure). This puts the boiling and freezing points of water exactly 180 degrees apart. Therefore, a degree on the Fahrenheit scale is 1/180 of the interval between the freezing point and the boiling point of water. Absolute zero is defined as -459.67°F.

Step-by-step explanation:

put it into ur own words ig, sorry that no1 answered it 4 u :(

5 0

3 years ago

Ava wrote the expression 4 minus 2 Over 3 minus 1 to determine the slope of a line. Which table might represent Ava’s line?

Genrish500 [490]

Answer:option 3

Step-by-step explanation:i got it right

6 0

2 years ago

Read 2 more answers

Please could I have some help :)

nirvana33 [79]

Answer:

a) x = 128 degrees

b) Angle APD is the arc angle, which is equal to the central angle x subtended by the arc. Therefore angle APD = 128 degrees (and not 116 degrees)

Step-by-step explanation:

Given:

attached diagram

ABC is a straight line

Solution:

a) Find x

ABC is a straight line

angle ABD = supplement of CBD = 180-CBD = 180-116 = 64 degrees.

x is the central angle of the arc APD

so angle ABD is the inscribed angle which equals half of the arc angle =>

angle ABD = x/2 = 64 degrees

Solve for x

x/2 = 64

x = 2*64

x = 128 degrees

Angle APD is the arc angle, which is equal to the central angle x subtended by the arc. Therefore angle APD = 128 degrees (and not 116 degrees)

5 0

3 years ago

Read 2 more answers

In JKL, k=4.1 cm,j=3.8 cm and angle J=Q3^ Find all possible values of angle K , to the nearest inch of a degree .

spayn [35]

Answer:

74.0°

Step-by-step explanation:

In triangle JKL, k = 4.1 cm, j = 3.8 cm and ∠J=63°. Find all possible values of angle K, to the nearest 10th of a degree

Solution:

A triangle is a polygon with three sides and three angles. Types of triangles are right angled triangle, scalene triangle, equilateral triangle and isosceles triangle.

Given a triangle with angles A, B, C and the corresponding sides opposite to the angles as a, b, c. Sine rule states that for the triangle, the following holds:

$\frac{a}{sin(A)}=\frac{b}{sin(B)}=\frac{c}{sin(C)}$

In triangle JKL, k=4.1 cm, j=3.8 cm and angle J=63°.

Using sine rule, we can find ∠K:

$\frac{k}{sin(K)}=\frac{j}{sin(J)} \\\\\frac{4.1}{sin(K)}=\frac{3.8}{sin(63)} \\\\sin(K)=\frac{4.1*sin(63)}{3.8}\\\\sin(K)=0.9613\\\\K=sin^{-1} (0.9613)\\\\K=74.0^o \\$

6 0

2 years ago

Calculate the straight line distance between the points (-10, -7) and (-8,1).<br> G.2(B)

tia_tia [17]

Answer:

2√(17) or about 8.2462 units.

Step-by-step explanation:

We want to determine the distance between the two points (-10, -7) and (-8, 1).

We can use the distance formula. Recall that:

$\displaystyle d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Substitute and evaluate:

$\displaystyle \begin{aligned} d &= \sqrt{((-10)-(-8))^2 + ((-7) - (1))^2} \\ \\ &=\sqrt{(-2)^2+(-8)^2} \\ \\ &= \sqrt{(4) + (64)} \\ \\ &= \sqrt{68}\\ \\ &= 2\sqrt{17}\end{aligned}$

Hence, the distance between (-10, -7) and (-8, 1) is 2√(17) units or about 8.2462 units.

4 0

2 years ago