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Goryan [66]
3 years ago
6

If the parent function is f(x) = x2 and its transformed function is g(x) = 2(x − 1)2 + 2, how is the graph of g(x) transformed f

rom the graph of its parent function?
stretch, shift along the y–axis, and shift along the x–axis
shift along the x–axis and the y–axis
reflection only
stretch along the y–axis and reflection through the origin
Mathematics
2 answers:
Studentka2010 [4]3 years ago
8 0

Answer:

Option A is the correct choice.

Step-by-step explanation:  

We have been given a parent function f(x)=x^2 and its transformed function is g(x)=2(x-1)^2+2. We are asked to find the transformation rules used to function f(x) to get g(x).

First of all let us recall the translation rules.  

f(x-a)\rightarrow\text{Graph shifted to the right by a units}

f(x)+a\rightarrow\text{Graph shifted upwards by a units}

a*f(x)\rightarrow\text{Graph stretches vertically, if a}>1

Upon looking at transformation rules we can see that the graph of g(x) is vertically stretched by a scale factor of 2. It is also shifted along the y-axis by 2 units upwards and along the x-axis by 1 unit to to the right.

Therefore, option A is the correct choice.

Galina-37 [17]3 years ago
7 0
The answer is A. g(x) is a vertical stretch and shift over both axes.
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A triangle weighs 3 grams and a circle weighs 6 grams. Find the weight of a square in Hanger A and the weight of a pentagon in H
Zanzabum

Answer:

Equation of Hanger A:

x + y = z

z = 9 grams

Equation for hanger B

x + y = p

p = 9 grams

Step-by-step explanation:

Note: This question is not complete, and lacks necessary data to answer this question. But for the sack of concept, we wil be solving this question using our own data.

Data given:

Triangle weight = 3 grams

Circle weight = 6 grams

There are two hangers A and B.

We have to find weight of the square in Hanger A and weight of the pentagon in Hanger B.

So, for your understanding I have drawn the two hangers A and B. In A we have triangle and circle on the LHS and the square on the right. On the other hand, we have pentagon on the right and triangle and circle.

Sketch is attached in the attachment.

Let's suppose: Hanger A is balanced, So,

Triangle weight = 3 grams = x

Circle weight = 6 grams = y

weight of the pentagon in Hanger B = p

weight of the square in Hanger A = z =?

So,

Equation of Hanger A:

x + y = z

z = 3 + 6

z = 9 grams  = weight of the square in Hanger A

Similarly for Hanger B.

Equation for hanger B

x + y = p

p = 3 + 6

p = 9 grams

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Step-by-step explanation:

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Step-by-step explanation:

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