Answer:
10kN
Explanation:
Given data
m1= 50kg
u1= 3m/s
m2= 100kg
u2= 6m/s
v1= 2m/s
time= 0.04s
let us find the final velocity of Bruce v1
from the conservation of linear momentum
m1u1+m2u2=m1v1+m2v2
substitute
50*3+100*6= 50*v1+100*2
150+600=50v1+200
750-200=50v1
550= 50v1
divide both sides by 50
v1= 550/50
v1=11 m/s
From
F= mΔv/t
for Bruce
F=50*(11-3)/0.04
F=50*8/0.04
F=400/0.04
F=10000
F=10kN
for Max
F=100*(6-2)/0.04
F=100*4/0.04
F=400/0.04
F=10000
F=10kN
Answer: ZnSO4 + Li2CO3 = ZnCO3 + Li2SO4 - Chemical Equation Balancer
Equation is already balanced.
Explanation: ZnSO4 + Li2CO3 = ZnCO3 + Li2SO4
1) <u>Newton</u><u> </u> <u>first</u><u> </u> <u>law</u><u> </u><u>of</u><u> </u><u>motion</u>: state“If a body is at rest it reamain at rest and if it is in a motion it continu its motion unless a net external force acting on it”
This law also called <u>law</u><u> </u><u>of</u><u> </u><u>inertia</u><u> </u><u> </u>
2)<u> </u><u>Newton</u><u> </u><u>second</u><u> </u><u>law</u><u> </u><u>of</u><u> </u><u>motion</u><u>:</u><u> </u>states that ‟acceleration to the force acting on the body and inversky proportional to the <u>mass</u><u> </u> of the body”
3)<u> </u><u>Newton's third law of motion</u><u>:</u> It is not possible to exert a force abody with out the body exerting a forces in the opposite direction.
These forces are called <u>action</u><u> </u> and <u>reaction</u><u> </u> forces
hope it's helpful ❤❤❤❤❤❤
THANK YOU.
An increase in average speed of 1 km/h typi- cally results in a 3% higher risk of a crash involving injury, with a 4–5% increase for crashes that result in fatalities. — Speed also contributes to the severity of the impact when a collision does occur. Hope this helps!
We have to convert Gm/s to m/s.
As 
Therefore the speed of light in vacuum,

Thus, the speed of light in m/s is 