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alexgriva [62]
3 years ago
13

Imagine that you work for a conservation organization. Your job is to make recommendations to restore an area of a prairie that

has been damaged by fire. Provide three ways in which the damaged area could be restored by human activities.
Physics
1 answer:
ella [17]3 years ago
7 0

Answer:

The damaged prairie area can be restored through <em>site preparation, replanting and putting species back on the landscape.</em>

Explanation:

Prairie- this is a type of habitat with mostly grasses. It also consists of trees, occasional shrubs and flowering plants. This can be found around the world and is <em>ecologically important for providing habitats for native animals and insects.</em> It is perfectly adapted to the climate and<u><em> requires minimal maintenance.</em></u>

Once a prairie is damaged, it becomes an essential move to restore it immediately. This can be done through different human activities such as the following:

1. Site preparation- before doing anything else, it would be best to prepare the prairie site by removing debris from the fire. This will make everything easier once you start planting the crops or plants.

2. Replanting- this is probably the most essential move you can do. It would be best to plant high quality food plants that would provide nectar, pollen and seeds throughout the season. This will entice many birds and butterflies into the area. It will also make the native plants abundant which will, in turn, increase ecological diversity.

3. Putting species back on the landscape- when a wildfire occurs, it is a common sense that species also run away from their home (habitat). In order to create that natural habitat again, it would be best to put the species back to where they belong so they can restart their lives. This will resume the natural food webs and nutrient cycles.

You might be interested in
considere que o calor específico de um material presente nas cinzas seja c=0,8j/gc. Supondo que esse material entre na turbina a
drek231 [11]

Answer:

3120J

Explanation:

Given parameters:

C  = Specific heat capacity  = 0.8J/g°C

Initial temperature  = 20°C

Mass given   = 5g

Final temperature  = 800°C

Unknown:

Energy given to the mass  = ?

Solution:

To find the energy given to the mass, let us simply use the expression below:

          H   =   m   c   ΔT

H is the unknown, the energy supplied

m is the mass of the substance

c is the specific heat capacity

ΔT is the change in temperature

Input the variables;

            H    = 5  x   0.8    x    (800 - 20)  = 3120J

7 0
3 years ago
PLS HELP WITH THIS FOR BRAINLIST IF ITS RIGHT
Zolol [24]

Answer:

the first one is Primary

the second one I think it's Mature but I don't know

5 0
3 years ago
A 1300-N crate rests on the floor. How much work is required to move it at constant speed (a)
kherson [118]

a) The work done is 920 J

b) The work done is 5200 J

Explanation:

a)

In this first part of the problem, the crate is moved horizontally at constant speed.

The work required in this case is given by

W=Fd cos \theta

where

F is the magnitude of the force applied

d is the displacement of the crate

\theta is the angle between the direction of the force and of the displacement

Here the crate is moved at constant speed: this means that the acceleration of the crate is zero, and so according to Newton's second law, the net force on the crate is zero: this means that the force applied, F, must be equal to the force of friction (but in opposite direction), so

F = 230 N

The displacement is

d = 4.0 m

And the angle is \theta=0^{\circ}, since the force is applied horizontally. Therefore, the work done is

W=(230)(4.0)(cos 0^{\circ})=920 J

b)

In this case, the crate is moved vertically. The force that must be applied to lift the crate must be equal to the weight of the crate (in order to move it a constant speed), therefore

F = W = 1300 N

The displacement this time is again

d = 4.0 m

And the angle is \theta=0^{\circ}, since the force is applied vertically, and the crate is moved also vertically. Therefore, the work done on the crate this time is

W=(1300)(4.0)(cos 0^{\circ})=5200 J

Learn more about work:

brainly.com/question/6763771

brainly.com/question/6443626

#LearnwithBrainly

4 0
3 years ago
A test tube of length L and cross-sectional area A is submerged in water with the open end down so that the edge of the tube is
Margaret [11]

Answer:

if we measure the change in height of the gas within the had and obtain a straight line in relation to the depth we can conclude that the air complies with Boye's law.

Explanation:

The air in the tube can be considered an ideal gas,

           P V = nR T

In that case we have the tube in the air where the pressure is P1 = P_atm, then we introduce the tube to the water to a depth H

For pressure the open end of the tube is

         P₂ = P_atm + ρ g H

Let's write the gas equation for the colon

            P₁ V₁ = P₂ V₂

            P_atm V₁ = (P_atm + ρ g H) V₂

             V₂ = V₁    P_atm / (P_atm + ρ g h)

If the air obeys Boyle's law e; volume within the had must decrease due to the increase in pressure, if we measure the change in height of the gas within the had and obtain a straight line in relation to the depth we can conclude that the air complies with Boye's law.

The main assumption is that the temperature during the experiment does not change

6 0
3 years ago
A car travels at a speed of 40 m/s for 29.0 s;<br>what is the distance traveled by the car?
lianna [129]

Answer: 1160 m

Explanation:

Speed = distance / time. Plug in 40 m/s for speed and 29 s for time in order to get the distance, 1160 m.

8 0
2 years ago
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