Answer:
5 metre.
Explanation:
Wavelength = Velocity / Frequency
= 23,000/ 4,500
= 5 metre.
Answer:
4kg
Explanation:
Given parameters:
Kinetic energy = 1.6J
Velocity = 0.2m/s
Unknown:
Mass of the body = ?
Solution:
The kinetic energy of a body is the energy due to the motion of the body.
It is mathematically expressed as;
Kinetic energy =
m v²
m is the mass
v is the velocity
1.6 =
x 0.2 x v²
1.6 = 0.1v²
v² = 16
v = 4kg
Complete Question:
A 59.1 g sample of iron is put into a calorimeter (see sketch attached) that contains 100.0 g of water. The iron sample starts off at 85.0 °C and the temperature of the water starts off at 23.0 °C. When the temperature of the water stops changing it's 27.6 °C. The pressure remains constant at 1 atm.
Calculate the specific heat capacity of iron according to this experiment. Be sure your answer is rounded to the correct number of significant digits
(Question attached)
Answer:

(rounded to 1 decimal place)
Explanation:
A calorimeter is used to measure the heat of chemical or physical reactions. The example given in the question is using the calorimeter to determine the specific heat capacity of iron.
When the system reaches equilibrium the iron and water will be the same temperature,
. The energy lost from the iron will be equal to the energy gained by the water. It is assumed that the only heat exchange is between the iron and water and no exchange with the surroundings.
(Eq 1)
(Eq 2)
Water:

Iron:

Substituting Eq 1 into Eq 2 and details extracted from the question:




The redshift of light from galaxies and the uniform distribution of cosmic background radiation
Answer:
A) ΔU = 3.9 × 10^(10) J
B) v = 8420.75 m/s
Explanation:
We are given;
Potential Difference; V = 1.3 × 10^(9) V
Charge; Q = 30 C
A) Formula for change in energy of transferred charge is given as;
ΔU = QV
Plugging in the relevant values gives;
ΔU = 30 × 1.3 × 10^(9)
ΔU = 3.9 × 10^(10) J
B) We are told that this energy gotten above is used to accelerate a 1100 kg car from rest.
This means that the initial potential energy will be equal to the final kinetic energy since all the potential energy will be converted to kinetic energy.
Thus;
P.E = K.E
ΔU = ½mv²
Where v is final velocity.
Plugging in the relevant values;
3.9 × 10^(10) = ½ × 1100 × v²
v² = [7.8 × 10^(8)]/11
v² = 70909090.9090909
v = √70909090.9090909
v = 8420.75 m/s