The correct answer is option (a) i.e. the equilibrium constant is 0.0167
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We know,
The equilibrium constant is kc = Concentration of product/ concentartion of reactants,
kc = [C][D] / [A][B],
Now,
kc= [4.00]*[4.0] / ( [9.60] * [10.00] ) = 0.166 </span>≈ 0.167
Thus, the equilibrium constant is 0.0167
Answer:
6.25 g
Explanation:
From the question given above, the following data were obtained:
Half-life (t½) = 68.8 years
Time (t) = 344 years
Original amount (N₀) = 200 g
Amount remaining (N) =?
Next, we shall determine the number of half-lives that has elapsed. This can be obtained as follow:
Half-life (t½) = 68.8 years
Time (t) = 344 years
Number of half-lives (n) =
n = t / t½
n = 344 / 68.8
n = 5
Thus, 5 half-lives has elapsed.
Finally, we shall determine the amount of the Uranium-232 that remains. This can be obtained as follow:
Original amount (N₀) = 200 g
Number of half-lives (n) = 5
Amount remaining (N) =?
N = 1/2ⁿ × N₀
N = 1/2⁵ × 200
N = 1/32 × 200
N = 200 / 32
N = 6.25 g
Thus, the amount of Uranium-232 that remains is 6.25 g
Answer: 1. magnesium hydroxide + sulfuric acid = magnesium sulphate + water
2. calcium hydroxide + hydrochloric acid = calcium chloride + water
3. lead hydroxide + nitric acid = lead nitrate + water
4. sodium hydroxide + sulfuric acid = sodium sulphate + water
5. potassium hydroxide + citric acid = potassium citrate + water
6. silver hydroxide + hydrochloric acid = silver chloride + water
7. aluminium hydroxide + phosphoric acid = aluminium phosphate + water
Explanation:
A double displacement reaction is one in which exchange of ions take place. The salts which are soluble in water are designated by symbol (aq) and those which are insoluble in water and remain in solid form are represented by (s) after their chemical formulas.
The balanced chemical equations are :
1. magnesium hydroxide + sulfuric acid = magnesium sulphate + water
2. calcium hydroxide + hydrochloric acid = calcium chloride + water
3. lead hydroxide + nitric acid = lead nitrate + water
4. sodium hydroxide + sulfuric acid = sodium sulphate + water
5. potassium hydroxide + citric acid = potassium citrate + water
6. silver hydroxide + hydrochloric acid = silver chloride + water
7. aluminium hydroxide + phosphoric acid = aluminium phosphate + water