All categories

3 years ago

The fossils in line 4 __ are the ones in line 1

Chemistry

2 answers:

Alex777 [14]3 years ago

8 0

I’m sorry I didn’t understand can you please add more details please thank you

dem82 [27]3 years ago

6 0

Fossils in line 4 are older than the ones in line 1. Fossils in line 1 are the youngest.

You might be interested in

What two molecules were condensed in an aldol condensation to produce (ch3)3cch=chcoch3?

inessss [21]

The given compound is being synthesized by condensing Acetone and Pivaldehyde (Trimethylacetaldehyde).

First Acetone is treated with Base, the base abstracts the mildly acidic proton present at alpha position to carbonyl group. The resulting specie called enolate act as a nucleophile and attacks on highly reactive aldehyde which upon dehydration yields the Aldol Product. The Reaction is as follow,

5 0

3 years ago

"acid is responsible for the odor in rancid butter. a solution of 0.25 m butyric acid has a ph of 2.71. what is the ka for"

Salsk061 [2.6K]

Answer:- The Ka for the acid is $1.53*10^-^5$ .

Solution:- In general, monoprotic acid could be represented by HA. The dissociation equation for the ionization of HA is written as:

HA(aq)\rightarrow H^+(aq) + A^-(aq)

Now, we make the ice table for this equation as:

HA(aq)\rightarrow H^+(aq) + A^-(aq)

I 0.25 0 0

C -X +X +X

E (0.25 - X) X X

where, I stands for initial concentration, C stands for change in concentration and E stands for equilibrium concentration.

X is the change in concentration and from ice table it's same as the concentration of hydrogen ion that is calculated from given pH.

$Ka = [H^+][A^-]\frac{1}{HA}$

Where, Ka is the acid ionization constant. Let's plug in the values.

$Ka = \frac{X^2}{0.25-X}$

Let's calculate the value of X first using the equation:

$pH = -log[H^+]$ [/tex]

on taking antilog ob above equation we get:

$[H^+]=10^-^p^H$

$[H^+]=10^-^2^.^7^1$

$[H^+]$ = 0.00195

So, X = 0.001195

Let's plug in this value of X in the equation:-

$Ka=\frac{(0.00195)^2}{0.25-0.00195}$

$Ka=1.53*10^-^5$

So, the value of Ka for butyric acid is $1.53*10^-^5$ .

8 0

3 years ago

Read 2 more answers

Glycerol boils at a high temperature than water. What does this indicate about the attractive forces of glycerol?

forsale [732]

Glycerol attractive forces are great than water. The harder to break, the more energy is needed.

5 0

3 years ago

In the reaction N2(g) + O2(g) 2NO(g), how will increasing pressure on the system affect the equilibrium?

Leno4ka [110]

The pressure increase does not affect the equilibrium shift reaction.

4 0

3 years ago

Read 2 more answers

I don’t understand this question

zhannawk [14.2K]

Since they both have the same momentum, the object with the larger mass has a small velocity. (Remember that mass and velocity are inversely proportional with
p=mv.) Therefore, the smaller object will have the larger KE. (KE = 1/2 ^2)

8 0

3 years ago