Question

What points are represent the center of a circle whose equation is (x-3) power 2 + (y-2) power 2 =16?

Answer 1

Answer:

centre = (3, 2) and radius = 4

Step-by-step explanation:

the equation of a circle in standard form is

(x - h)² + (y - k)² = r²

where (h, k) are the coordinates of the centre and r is the radius

(x - 3)² + (y - 2)² = 16 ← is in standard form

with centre = (3, 2) and r = $\sqrt{16}$ = 4