Quiet metabolism account for about 50% of the average person’s daily energy expenditures
A metabolism is a balancing act that involves two types of simultaneous activities: building up body tissues and energy stores (called anabolism) and breaking down body tissues and energy stores to get additional fuel for body functions (called catabolism)
Some of them are catabolic routes, such as glycolysis (the breaking of glucose), -oxidation (the breakdown of fatty acids), and amino acid catabolism. Others are anabolic pathways, such as those involved in energy storage (such as glycogenosis) and triglyceride synthesis (lipogenesis)
Metabolic pathways include the processes of producing and decomposing glucose molecules. A metabolic pathway is a chain of chemical reactions that feed off of one another.
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The gravitional force that the earth has on the moon would be less because the distance increased
Nucleases are the enzymes that are unique to the pancreas. These are enzymes which break down nucleic acids DNA and RNA into nucleotides. When these nucleotides reach the ileum, they are further degraded or digested into sugars, bases and phosphates. These nucleases are known as DNAase and RNAase
Other pancreatic enzymes such as amylase and protease are also produced by other digestive organs such as the salivary glands and the small intestine respectively. However no other digestive organ has been known to produce nucleases apart from the pancreas.
Nucleases are of two main types, namely exonucleases which cut off the end of a nucleotide and endonucleases which will cut out certain nucleotide sequences right in the middle of a nucleic acid.
Answer:
Frequency of allele A1- 0.41
Explanation:
In Hardy weinberg equilibrium,
P refers to the dominant allele
q refers to the recessive allele
The allele frequency will be p+q=1
The genotypic frequency is- P²+q²+2pq=1
P²= genotype of dominant trait ( A1A1)- 77
2pq= genotype of heterozygotes (2pq)- 65
q²= genotype of recessive trait (A2A2)- 123
Total number of offsprings= 77+ 65+ 123
= 265
Now to calculate allele frequency of A1=
= 77/265 + 1/2( 65//265)
= 0.290+ 0.122
= 0.413
Thus, 0.41 is correct.
