Answer:
343 m/s
Explanation:
Velocity Formula (Wave): v = fλ
<em>v</em> - velocity
<em>f</em> - frequency
<em>λ</em> - wavelength
We are given <em>f</em> = 23.0 and <em>λ</em> = 14.9. Simply plug it into the formula:
v = 23.0(14.9)
v = 342.7
v ≈ 343
Answer: Option (a) is the correct answer.
Explanation:
The given data is as follows.
= 4.19 ![kJ/kg ^{o}C](https://tex.z-dn.net/?f=kJ%2Fkg%20%5E%7Bo%7DC)
= 1.9 ![kJ/kg ^{o}C](https://tex.z-dn.net/?f=kJ%2Fkg%20%5E%7Bo%7DC)
Heat of vaporization (
) at 1 atm and
is 2259 kJ/kg
= 0
Therefore, calculate the enthalpy of water vapor at 1 atm and
as follows.
=
+
= 0 + 2259 kJ/kg
= 2259 kJ/kg
As the desired temperature is given
and effect of pressure is not considered. Hence, enthalpy of liquid water at 10 bar and
is calculated as follows.
= ![0 + 4.19 kJ/kg ^{o}C \times (179.9^{o}C - 100^{o}C)](https://tex.z-dn.net/?f=0%20%2B%204.19%20kJ%2Fkg%20%5E%7Bo%7DC%20%5Ctimes%20%28179.9%5E%7Bo%7DC%20-%20100%5E%7Bo%7DC%29)
= 334.781 kJ/kg
Hence, enthalpy of water vapor at 10 bar and
is calculated as follows.
![H^{D}_{vap} = H^{o}_{vap} + C_{p}_{vap} \times (T_{D} - T_{o})](https://tex.z-dn.net/?f=H%5E%7BD%7D_%7Bvap%7D%20%3D%20H%5E%7Bo%7D_%7Bvap%7D%20%2B%20C_%7Bp%7D_%7Bvap%7D%20%5Ctimes%20%28T_%7BD%7D%20-%20T_%7Bo%7D%29)
=
= 2410.81 kJ/kg
Therefore, calculate the latent heat of vaporization at 10 bar and
as follows.
=
= 2410.81 kJ/kg - 334.781 kJ/kg
= 2076.029 kJ/kg
or, = 2076 kJ/kg
Thus, we can conclude that at 10 bar and
latent heat of vaporization is 2076 kJ/kg.
<h3>
![{\tt{\red{\underline{\underline{\huge{Question:}}}}}}](https://tex.z-dn.net/?f=%7B%5Ctt%7B%5Cred%7B%5Cunderline%7B%5Cunderline%7B%5Chuge%7BQuestion%3A%7D%7D%7D%7D%7D%7D)
</h3>
<h3>What science govern in nanostructure?</h3>
<h3>
![{\tt{\red{\underline{\underline{\huge{Answer:}}}}}}](https://tex.z-dn.net/?f=%7B%5Ctt%7B%5Cred%7B%5Cunderline%7B%5Cunderline%7B%5Chuge%7BAnswer%3A%7D%7D%7D%7D%7D%7D)
</h3>
The materials having dimensions between 1 and 100 nanometeres are called nonostructures and the science that operates at nano scale is called Nanotechnology.
![\huge\boxed{\fcolorbox{blue}{red}{Thank \: you}}](https://tex.z-dn.net/?f=%5Chuge%5Cboxed%7B%5Cfcolorbox%7Bblue%7D%7Bred%7D%7BThank%20%5C%3A%20you%7D%7D%20)