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Serhud [2]
3 years ago
8

According to Le Chatelier’s principle, what always happens to the equilibrium of a reaction when the temperature is reduced?

Chemistry
2 answers:
Tasya [4]3 years ago
5 0
It always shift to the direction where balance out the reaction
here 
<span>It shifts in the exothermic direction.</span>
klemol [59]3 years ago
5 0

Answer: The correct option is C.

Explanation: Le-Chatelier's principle is a principle in which the equilibrium adjusts itself whenever there is a change in the equilibrium conditions (pressure, temperature and concentration).

When reaction is an exothermic reaction, it means that the heat is released (increase in temperature) and when it is an endothermic reaction, it means that the heat is being absorbed (decrease in temperature).

So, in a reaction, when the temperature is reduced, the equilibrium reaction will shift in the direction where there is an increase in temperature, which is the exothermic reaction.

Hence, the correct option is C.

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Question: If red dye is added to cold water and blue dye is added to warm water, which dye will
vlada-n [284]

Answer:

Blue dye spreads out quicker

Explanation:

This is because the dye gets spread out by water molecules. Warm water has faster moving water molecules than cold water.

6 0
3 years ago
Read 2 more answers
Se ha añadido un evaporador para una alimentación de 11500 kg/dia de zumo de pomelo de forma que evapore 3000 kg/dia de agua por
mamaluj [8]

Answer:

37 %.

Explanation:

¡Hola!

En este caso, para el problema descrito, conocemos la corriente de entrada y la de salida del agua, por lo que podemos obtener el flujo de la corriente que contiene el zumo a la salida una vez el agua fue evaporada:

F_{sol}=11500kg/dia-3000kg/dia=8500 kg/dia

Luego, por medio de un balance de zumo de limón en el evaporador en el cual la cantidad que entra es igual a la que sale con sus respectivas concentraciones:

x_z^{entra}*11500kg/dia=x_z^{sale}*8500kg/dia

Como la concentración del zumo a la salida es del 50 % (0.50), la de entrada es:

x_z^{entra}=\frac{x_z^{sale}*8500kg/dia}{11500kg/dia} =\frac{0.50*8500kg/dia}{11500 kg/dia}\\ \\x_z^{entra}=0.37

Que es igual al 37%.

¡Saludos!

6 0
4 years ago
Why do you think steeples and roofs might appear green, but a copper square does not?
Masteriza [31]
Because the copper roofs, have been outside for a while and oxidization has occurred.
When metals become oxidized they rust, but when copper becomes oxidized, it turns greenish.
So copper roofs oxidize and turn green from being outside and a copper square doesn’t if it’s inside.
8 0
2 years ago
Determine the maximum number of moles of product that can be produced from 7.0 mol al and 8.0 mol cl2 according to the equation
Vilka [71]
The balanced chemical reaction is

<span>2al + 3cl2 = 2alcl3

To determine the maximum amount of product, we need to determine which is the limiting reactant. Then, use the initial amount of that reactant to calculate the amount of the product that would be produced. We do as follows:

7 mol Al (3 mol Cl2 / 2 mol Al) = 10.5 mol Cl2
8 mol Cl2 ( 2 mol Al / 3 mol Cl2) = 5.3 mol Al
Thus, it is Cl2 that is the limiting reactant.

8 mol Cl2 ( 2 mol AlCl3 / 3 mol Cl2) = 5.3 moles of AlCl3 is produced</span>
5 0
4 years ago
Explain why fluorine has a smaller atomic radius than both oxygen and chlorine
Alex777 [14]

Answer:

1) Has a smaller radius than oxygen because of the increased electromagnetic attraction of the nuclei

2) Has a smaller radius than chlorine because all the electrons of F have lower energy levels and have less repulsion of other electrons and hence are more attracted to the nuclei .

Explanation:

Further the electrons are from the nuclei , the bigger the atomic radius is.

(+) attraction of electrons to the nuclei, (-) repulsion of the electrons away from the nuclei.

1) From O to F:

(+) there is one more proton --> Stronger positive charge of the nuclei means that the electrons are attracted more , then they come closer to it and therefore the radius decreases

(-) There is one more electron --> Every electron is repulsed by others away from the nuclei --> the radius increases. But this effect is not so strong because the new electron is added at the same energy level.

Overall the (+) effect is stronger than the (-) effect --> Radius decreases from O to F

2) From F to Cl

(+) there is one more protons --> Same effect as before

(-) There is one more electron --> Every electron is repulsed by others away from the nuclei. But this time the new electrons have a higher energy level --> Meaning that they are less attracted and hence the radius increases.

And also the other inner layers of electrons (electrons of lower energy levels) repulse this new external layer of electrons more effectively than the case of O  --> Strong repulsion effect (called electron shielding effect) --> Radius increases

Overall the (-) effect is stronger than the (+) effect --> Radius increases from F to Cl  (or decreases from Cl to F)

5 0
3 years ago
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