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Nesterboy [21]
3 years ago
15

Write the net ionic equation for the reaction of aqueous copper(II) chloride with aqueous sodium phosphate. Remember to include

the states of matter.
Chemistry
1 answer:
sergeinik [125]3 years ago
7 0

Answer:

3 Cu²⁺(aq) + 2 PO₄³⁻(aq) ⇒ Cu₃(PO₄)₂(s)

Explanation:

Let's consider the molecular equation between aqueous copper(II) chloride and aqueous sodium phosphate.

3 CuCl₂(aq) + 2 Na₃PO₄(aq) ⇒ 6 NaCl(aq) + Cu₃(PO₄)₂(s)

The complete ionic equation includes all the ions and insoluble species.

3 Cu²⁺(aq) + 6 Cl⁻(aq) + 6 Na⁺(aq) + 2 PO₄³⁻(aq) ⇒ 6 Na⁺(aq) + 6 Cl⁻(aq) + Cu₃(PO₄)₂(s)

The net ionic equation includes only the ions that participate in the reaction (not spectator ions) and insoluble species.

3 Cu²⁺(aq) + 2 PO₄³⁻(aq) ⇒ Cu₃(PO₄)₂(s)

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A mixture of 0.220 moles rn, 0.350 moles o2 and 0.640 moles ar has a total pressure of 2.95 atm. what is the pressure of o2? a m
EastWind [94]

Answer:

0.85 atm

Explanation:

We start by getting the total number of moles of all gases.

Total moles = 0.220 + 0.350 + 0.640 = 1.21 mol

Then we get the fraction of Oxygen moles and multiply by the total pressure;

The pressure of O2 = 0.350 mol / 1.21 mol x 2.95 atm  

                                = 0.85 atm

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4 years ago
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astraxan [27]
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3 years ago
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A jeweler is making sapphire rings using 2 sapphires on every 1 ring. If the jeweler has 12 sapphires and 10 rings, what is the
user100 [1]

Answer: The theoretical yield is 6 rings.

Explanation:

Theoretical yield is predicted or estimated value.

Jeweler used 2 sapphires for 1 ring

Then for each sapphire there will be = \frac{1}{2} rings are used

For 12 sapphire = \frac{1}{2}\times 12=6 rings will be used

Out of 10 rings 6 rings with 2 sapphires will be made.

The theoretical yield is 6 rings.

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3 years ago
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how many grams of potassium chloride, KCL(molar mass is 74.55g/mol) are produced if 25 grams of potassium chlorate KClo^3 decomp
JulsSmile [24]

Answer:

                     Mass = 15.20 g of KCl

Explanation:

                    The balance chemical equation for the decomposition of KClO₃ is as follow;

                                            2 KClO₃ = 2 KCl + 3 O₂

Step 1: Calculate moles of KClO₃ as;

Moles = Mass / M/Mass

Moles = 25.0 g / 122.55 g/mol

Moles = 0.204 moles

Step 2: Find moles of KCl as;

According to equation,

                  2 moles of KClO₃ produces  =  2 moles of KCl

So,

               0.204 moles of KClO₃ will produce  =  X moles of KCl

Solving for X,

                       X = 2 mol × 0.204 mol / 2 mol

                       X = 0.204 mol of KCl

Step 3: Calculate mass of KCl as,

Mass = Moles × M.Mass

Mass = 0.204 mol × 74.55 g/mol

Mass = 15.20 g of KCl

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ivanzaharov [21]
It is true

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