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3 years ago

I need help!!!!! Select the atoms present in each of the following macromolecules

Biology

2 answers:

kirza4 [7]3 years ago

6 0

Answer:

cddb

Explanation:

hope i helped you out :)

harina [27]3 years ago

6 0

Answer: 1: option C, 2: option D, 3: option B, 4: option C.

Explanation:

1. Option C. Disaccharide.

Disaccharide is formed as a result of two monosaccharides joined by glycosidic linkage to form a disaccharide.

2. Option D. Starch.

Plants stored their manufactured glucose in form of starch. The glucose is manufactured during photosynthesis.

3. Option B. The R group.

The R group differs among amino acids, they are radicals and it determines the differences between these amino acids (this simply implies that the R group is the variable part of amino acids). The R groups are very essential because it is their properties that determines the structure and function of protein.

4. Option C.

Most tertiary structures can be either globular or fibrous. Generally, proteins such as enzymes which are basically non-structural proteins are globular, they look spherical.

The enzyme amylase is globular in shape therefore it is a tertiary structure protein.

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Select ALL the correct answers.

tekilochka [14]

Answer:

(b) The interquartile range of B is greater than the interquartile range of A.

(d) The median of A is the same as the median of B.

Explanation:

Given

$A = \{1, 4, 2, 2, 3, 1, 1, 2, 1\}$

$10th\ run = 9$

So:

$B = \{1, 4, 2, 2, 3, 1, 1, 2, 1,9\}$

Required

Select all true statements

(a) & (d) Median Comparisons

$A = \{1, 4, 2, 2, 3, 1, 1, 2, 1\}$ $B = \{1, 4, 2, 2, 3, 1, 1, 2, 1,9\}$

$n = 9$ $n = 10$

Arrange the data:

$A = \{1, 1, 1, 1, 2, 2, 2,3, 4\}$ $B = \{1,1,1,1,2,2,2,3,4,9\}$

$Median = \frac{n + 1}{2}th$

$Median = \frac{9 + 1}{2}th$ $Median = \frac{10 + 1}{2}th$

$Median = \frac{10}{2}th$ $Median = \frac{11}{2}th$

$Median = 5th$ $Median = 5.5}th$ --- average of 5th and 6th

$Median = 2$ $Median = \frac{2+2}{2} = 2$

Option (d) is correct because both have a median of: 2

(b) & (c) Interquartile Range Comparisons

$A = \{1, 1, 1, 1, 2, 2, 2,3, 4\}$ $B = \{1,1,1,1,2,2,2,3,4,9\}$

$n = 9$ $n = 10$

First, calculate the lower quartile (Q1)

$Q_1 = \frac{n + 1}{4}th$ [Odd n] $Q_1 = \frac{n}{4}th$ [Even n]

$Q_1 = \frac{9 + 1}{4}th$ $Q_1 = \frac{10}{4}th$

$Q_1 = \frac{10}{4}th$ $Q_1 = 2.5$

$Q_1 = 2.5th$

This means that:

$Q_1 = 2nd + 0.5(3rd - 2nd)$ $Q_1 = 2nd + 0.5(3rd - 2nd)$

$Q_1 = 1 + 0.5(1- 1)$ $Q_1 = 1+ 0.5(1 - 1)$

$Q_1 = 1$ $Q_1 = 1$

Next, calculate the upper quartile (Q3)

$Q_3 = \frac{3}{4}(n + 1)th$ [Odd n] $Q_3 = \frac{3}{4}(n)th$ [Even n]

$Q_3 = \frac{3}{4}(9 + 1)th$ $Q_3 = \frac{30}{4}th$

$Q_3 = \frac{30}{4}th$ $Q_3 = 7.5th$

$Q_3 = 7.5th$

This means that:

$Q_3 = 7th + 0.5(8th- 7th)$ $Q_3 = 7th + 0.5(8th- 7th)$

$Q_3 = 2 + 0.5(3- 2)$ $Q_3 = 2+ 0.5(4 - 2)$

$Q_3 = 2.5$ $Q_3 = 3$

The interquartile range is $IQR = Q_3 - Q_1$

So, we have:

$IQR = 2.5 - 1$ $IQR = 3 - 1$

$IQR = 1.5$ $IQR =2$

(b) is true because B has a greater IQR than A

(e) This is false because some spread measures (which include quartiles and the interquartile range) changed when the 10th data is included.

The upper quartile and the interquartile range of A and B are not equal

8 0

3 years ago

A common feature of all organisms in the animal kingdom is that they are?

torisob [31]

They're all common in the fact that they have to eat others that have energy, because they in themselves cannot produce their own energy. All animals are multicellular.

6 0

2 years ago

Which part of the brain is responsible for coordinating muscle movements and maintaining balance?

mr Goodwill [35]

The Cerebellum is responsible for coordinating muscle movements and maintaining balance

7 0

3 years ago

If crossing over did not occur why will meiosis still increase genetic variation

tester [92]

Yes sir it will meiosis is my fav part of science

6 0

3 years ago

A ---- is a multi-level network of feeding interactions, through which

SpyIntel [72]

Answer:

1. Food web

HOPE IT HELP YOU 

THANKS FOR POINTS

3 0

3 years ago