Question

Problems solved by quadratic equations:x2 + 7x +12 = 0

Answer 1

This would be easer to factor
(x+3)(x+4)=0
x+3=0
x+4=0

x=-3 and -4

bu tif want quadratic

in form
ax^2+bx+c=0

x=$\frac{-b+/- \sqrt{b^2-4ac} }{2a}$

ax^2+bx+c=0
1x^2+7x+12=0
a=1
b=7
c=12
x=$\frac{-b+/- \sqrt{b^2-4ac} }{2a}$
x=$\frac{-7+/- \sqrt{7^2-4(1)(12)} }{2(1)}$
x=$\frac{-7+/- \sqrt{49-48} }{2}$
x=$\frac{-7+/- \sqrt{1} }{2}$
x=$\frac{-7+/- 1}{2}$
x=-6/2 or -8/2
x=-3 or -4