5+<img src="https://tex.z-dn.net/?f=x%5E%7B2%7D" id="TexFormula1" title="x^{2}" alt="x^{2}" align="absmiddle" class="latex-formu

Which input value produces the same output value for the two functions on the graph?

PIT_PIT [208]

Answer:

x = 1

Step-by-step explanation:

5 0

3 years ago

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A website manager has noticed that during the evening hours, about 5 people per minute check out from their shopping cart and m

Over [174]

Answer:

a) Poisson distribution

b) 99.33% probability that in any one minute at least one purchase is made

c) 0.05% probability that seven people make a purchase in the next four minutes

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

In which

x is the number of sucesses

e = 2.71828 is the Euler number

$\mu$ is the mean in the given time interval.

5 people per minute check out from their shopping cart and make an online purchase.

This means that $\mu = 5$

a) What model might you suggest to model the number of purchases per minute? 

The only information that we have is the mean number of an event(purchases) in a time interval. Each event is also independent fro each other. So you should suggest the Poisson distribution to model the number of purchases per minute.

b) What is the probability that in any one minute at least one purchase is made? 

Either no purchases are made, or at least one is. The sum of the probabilities of these events is 1. So

$P(X = 0) + P(X \geq 1) = 1$

We want to find $P(X \geq 1)$

So

$P(X \geq 1) = 1 - P(X = 0)$

In which

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 0) = \frac{e^{-5}*(5)^{0}}{(0)!} = 0.0067$

1 - 0.0067 = 0.9933.

99.33% probability that in any one minute at least one purchase is made

c) What is the probability that seven people make a purchase in the next four minutes?

The mean is 5 purchases in a minute. So, for 4 minutes

$\mu = 4*5 = 20$

We have to find P(X = 7).

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 0) = \frac{e^{-20}*(20)^{7}}{(7)!} = 0.0005$

0.05% probability that seven people make a purchase in the next four minutes

8 0

3 years ago

A random triangle is formed in some way, such that all pairs of angles have the same joint distribution. what is the correlation

Goryan [66]

Does it has a picture?

7 0

3 years ago

12x0.08 help me plss!!!

mel-nik [20]

Answer:

0.96

Step-by-step explanation:

6 0

2 years ago

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A city averages 14 hours of daylight in June (the longest days) and 10 in December (the shortest days). Assume that the number o

UNO [17]

The equation is given as

$y = 12 sin (6t - \pi /2) + 2$

<h3>The Amplitude </h3>

The Amplitude can be calculated as

$amplitude = \frac{max + min}{2}\\ amplitude = \frac{10+14}{2} = 12$

<h3>The Vertical Shift</h3>

The vertical shift is the average difference between the maximum and minimum.

$Vertical Shift = \frac{Max - Min}{2} = \frac{14-10}{2} = 2$

For b value

The Time Period will be twice the distance between max and min.

$time period = \frac{2\pi }{b} \\time period = 2 * distance between max and min\\b = \frac{2\pi }{2}*\frac{1}{b} = \frac{\pi }{6}$

<h3>The Period</h3>

The period is calculated as

$T = \frac{2\pi }{b} \\T = \frac{2\pi }{\frac{\pi }{b} } = 12$

The equation is given as

$y = 12 sin (6t - \pi /2) + 2$

Learn more on time period and amplitude here;

brainly.com/question/15531840

8 0

2 years ago