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3 years ago

Who ever answers this first gets brainlist What is 6^8

Mathematics

2 answers:

kumpel [21]3 years ago

7 0

Answer:

1679616

Step-by-step explanation:

gregori [183]3 years ago

5 0

Answer:

1679616

Step-by-step explanation:

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What is 15% or $48.32?

Alexxandr [17]

What I got is this: 15% of $48.32 = $7.25

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3 years ago

2 numbers greater than 19 that are divisible by 2, 3, 6 and 9

Umnica [9.8K]

9*6 = 54 which is also divisible by 2 and 3

another one would be 2*54 = 108

Answer 54 and 108.

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4 years ago

Show the formula for finding the area of a triangle. Then find the area of a right triangle with a base of 19 cm and a height of

snow_tiger [21]

The answer is 61.75 because you have to do base times height then divide that answer by two

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3 years ago

Graph the system below and write its solution (2x+y=-4 (y=-1/2x+2

Travka [436]

The solution is (-4,4)

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3 years ago

Scores of an IQ test have a bell-shaped distribution with a mean of 100 and a standard deviation of 17. Use the empirical rule

-BARSIC- [3]

Answer:

(a) 95% of people have an IQ score between 66 and 134.

(b) 32% of people have an IQ score of less than 83 or greater than 117.

(c) 16% of people have an IQ score greater than 117.

Step-by-step explanation:

We are given that scores of an IQ test have a bell-shaped distribution with a mean of 100 and a standard deviation of 17.

Let X = scores of an IQ test

SO, X ~ Normal( $\mu=100, \sigma^{2} = 17^{2}$ )

The z-score probability distribution for the normal distribution is given by;

Z = $\frac{X-\mu}{\sigma}$ ~ N(0,1)

Now, the empirical rule states that;

68% of the data values lie within 1 standard deviation from the mean.

95% of the data values lie within 2 standard deviations from the mean.

99.7% of the data values lie within 3 standard deviations from the mean.

(a) The percentage of people having an IQ score between 66 and 134 is given by;

z score for 66 = $\frac{X-\mu}{\sigma}$ = $\frac{66-100}{17}$ = -2

z score for 134 = $\frac{X-\mu}{\sigma}$ = $\frac{134-100}{17}$ = 2

This means that the percentage of people having an IQ score between 66 and 134 is 95%.

(b) Firstly, we have to find the percentage of people having an IQ score between 83 and 117;

z score for 83 = $\frac{X-\mu}{\sigma}$ = $\frac{83-100}{17}$ = -1

z score for 117 = $\frac{X-\mu}{\sigma}$ = $\frac{117-100}{17}$ = 1

This means that the percentage of people having an IQ score between 83 and 117 is 68%.

This means that the percentage of people having an IQ score of less than 83 or greater than 117 = 100% - 68% = 32%.

(c) In the above part, we find that there are 32% of the values that have an IQ score of less than 83 or greater than 117.

This means that half of this will be less than 83 and half of this will be greater than 117.

So, the percentage of people having an IQ score greater than 117 = $\frac{32\%}{2}$ = 16%.

8 0

3 years ago