F(x)=x^2+2x+1 & g(x)=3(x+1)^2
now, f(x)+g(x)
=x^2+2x+1+3(x+1)^2
=x^2+2x+1+3(x^2+2x+1)
=x^2+2x+1+3x^2+6x+3
=4x^2+8x+4<===answer(c)
next:
f(x)=x^2-1 & g(x)=x+3
now, f(g(x))=(x+3)^ -1
=x^2+6x+9-1
=x^2+6x+8<====answer(b)
i solve two of ur problems.
now try the 3rd one that is similar to no. 1
and try the last two urself.
Idk how many start cards there are o this problem cant be solved...
Each classroom donated around 320 cans(or more) of food.
320x28=8,960.
Answer:
Barb is correct she won by 10 points
Darius's=480
Barb=490
Product <em /><em /><em>is the answer to a multiplication problem.
Multiple is the product of the number and whole numbers.
Hopefully this helps! :D :D
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