3 years ago

All of the following are equal except

Mathematics

1 answer:

KengaRu [80]3 years ago

8 0

Except what? Where is the problem?

You might be interested in

Question 11 (2.5 points)

Rama09 [41]

Answer:

Step-by-step explanation:

The answer is d, because a represents adults, and c represent children. It's $45 per adult, so $45a, and $30 per child, so $30c. a+c is equal to 10, because that's how many tickets were purchased. $45a+$30c=345, because $345 is the total amount spent on tickets.

3 0

3 years ago

The greatest common factor of 3m2n + 12mn2 is

Karolina [17]

$3m^2n + 12mn^2=3mn\cdot(m+4n)$

6 0

3 years ago

Read 2 more answers

Help please?

Alla [95]

$\bf \begin{array}{clclll}
3^{1001}&\qquad &4^{1002}\\
\uparrow &&\uparrow \\
a&&b
\end{array}\\\\
-----------------------------\\\\
(a+b)^2-(a-b)^2\implies (a^2+2ab+b^2)-(a^2-2ab+b^2)
\\\\\\
a^2+2ab+b^2-a^2+2ab-b^2\implies 2ab+2ab\implies 4ab
\\\\\\
now\qquad 4(3^{1001})(4^{1002})=k12^{1001}\qquad 
\begin{cases}
12^{1001}\\
(4\cdot 3)^{1001}\\
4^{1001}\cdot 3^{1001}
\end{cases}$

$\bf \\\\\\
4(3^{1001})(4^{1002})=k(4^{1001}\cdot 3^{1001})\implies \cfrac{4(3^{1001})(4^{1002})}{4^{1001}\cdot 3^{1001}}=k
\\\\\\
4\cdot \cfrac{3^{1001}}{3^{1001}}\cdot \cfrac{4^{1002}}{4^{1001}}=k\implies 4\cdot 4^{1002}4^{-1001}=k\impliedby 
\begin{array}{llll}
\textit{same base}\\
\textit{add the}\\
exponents
\end{array}
\\\\\\
4\cdot 4^{1002-1001}=k\implies 4\cdot 4^1=k\implies 16=k$

6 0

3 years ago

Officials estimate that 320,000 Boston-area partygoers attended last year's Independence Day celebration on the banks of the Cha

Anna11 [10]

40 ton x 2000 = 80,000 pounds

320000/8000 = 40 pounds per person

7 0

3 years ago

Bananas are on sale for $0.39 per pound. Mr Schurter bought 3 x 3 /4 pounds of bananas. Which is closest to the amount he paid f

Anna71 [15]

It comes out to 0.8775 so it rounds to about $0.88

8 0

3 years ago