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ohaa [14]
3 years ago
7

The black graph is the graph of y=f(x). Choose the equation for the red graph.

Mathematics
1 answer:
FromTheMoon [43]3 years ago
4 0

Answer:

d

Step-by-step explanation:

The red graph is an enlargement of the black graph.

Note coordinates of vertices of black graph to coordinates of red graph

(2, 2 ) → (2, 4 )

(4, - 2 ) → (4, - 4 )

(- 2, - 2 ) → (- 2, - 4 )

The y- coordinates of the red graph are twice the y- coordinates of the black graph.

and

\frac{y}{2} = f(x) ← multiply both sides by 2

y = 2f(x) ← as required, thus

equation of red graph is

\frac{y}{2} = f(x) → d

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Alekssandra [29.7K]

Answer:

A

Answer is A.

Hope this helps.

3 0
3 years ago
Please help I will mark brainliest!
Ymorist [56]

Answer:

  A

Step-by-step explanation:

You know that the negative number with the largest magnitude is farthest to the left on the number line.

  3/4 = 9/12

  2/3 = 8/12

Then 3/4 > 2/3, so ...

  -3/4 < -2/3

7 0
3 years ago
F(1) = 5
MatroZZZ [7]

Answer:

a(7)=3645

Step-by-step explanation:

you have :

f(1) =a= 5

and from recursive rule: f(n) = r · f(n − 1) and f(n) = 3 · f(n − 1)

So r=3

then

a(n)=a*r^(n-1)

a(7)=5*3^(7-1)

a(7)=5*3^6=3645

<em>hope this helps</em>

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7 0
2 years ago
Need help ace<br><br> help pls
Alexandra [31]

Answer:

Hello I am an ace! answer: 8

Step-by-step explanation:

Volume for a cube is just length × width × height so you only need to know 1 for a cube because they will all be the same number so 8 is the answer because 8 × 8 × 8 = 512 Hope this helps!

8 0
3 years ago
I need help with Q9 c, I’ve done a and b if it helps, b=325 but I am just stuck on question 9C, I know the answer is 500N (as it
777dan777 [17]

Step-by-step explanation:

I know you've already done parts a and b, but I'll show the work for that before I do c.

Draw two free body diagrams, one for the car and one for the trailer.  The car pulls the trailer forward with a tension force T, so the trailer pulls backward on the car with an equal and opposite force T.

The car also has a 1200 N forward force from the engine, and a 200 N backwards force from resistance.

The trailer has a backwards resistance force of 100 N.

Sum of forces on the car:

∑F = ma

1200 − 200 − T = 900a

1000 − T = 900a

Sum of forces on the trailer:

∑F = ma

T − 100 = 300a

To solve the system of equations, first add the equations together.

1000 − 100 = 1200a

900 = 1200a

a = 0.75 m/s²

Plug back into either equation to find the tension force:

T = 325 N

Now for part c, draw new free body diagrams for the car and trailer.  This time, the car is pushing back on the trailer to slow it down.  So the trailer is pushing forward on the car with an equal and opposite force.  The magnitude of that tension force is given to be 100 N.

The car also has a backwards 200 N force from resistance, and a backwards brake force F.

The trailer has a backwards 100 N force from resistance.

Sum of forces on the car:

∑F = ma

100 − 200 − F = 900a

-100 − F = 900a

Sum of forces on the trailer:

∑F = ma

-100 − 100 = 300a

-200 = 300a

a = -⅔

Plugging into the first equation:

-100 − F = 900 (-⅔)

-100 − F = -600

F = 500 N

4 0
3 years ago
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